BalicantaYao

package hello;

public class OCR {

    public static void main(String[] args)
    {
        String first = "1ba";
        String second = "a1a";
        boolean res = Ocr(first, second);
        System.out.println(res);

BalicantaYao

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">

    <servlet>
        <servlet-name>SimpleServlet</servlet-name>
        <servlet-class>week3.SimpleServlet</servlet-class>
    </servlet>

BalicantaYao

1.給予 int x,請計算 y 值,其公式如下:
	y = 3 * x^2		若 x < -1
	y = x^3 + 3 * x - 3	若 -1 <= x <= 1
	y = 2 * x + 3		若 x > 1

2.給予三角形三邊長(int)a,b,c,請判斷是直角,銳角,鈍角,或非三角形.
	(註:假設邊長排序結果,a <= b <= c,則
		直角(right triangle): c*c = a*a + b*b
		鈍角(obtuse triangle): c*c > a*a + b*b
		銳角(sharp triangle): c*c < a*a + b*b

BalicantaYao

1.(數列反印) 亂數產生10個介於2~2000的偶數,依序存到陣列內,再反印之,
  輸出範例
  原始數列: 250 1400 890 126 1844 734 182 1922 36 976
	反印數列: 976 36 1922 182 734 1844 126 890 1400 250

2.(數列和) 亂數產生10個整數,值介於1-99之間,求10個整數和.

3.請寫一個 Method, 接收最大亂數值、最小亂數值產生一個落在範圍裡的亂數，並印出
public void printRandom(int max, int min){
} 

BalicantaYao

public class Student{

   // 靜態 -
   int score = 0;

   // 動態 -
   public void play(int hours){
       score = score - hours;
   }

BalicantaYao

1.(戶頭)
   實作一戶頭類別Account,內含私有餘額balance,型別實數,
   對外提供如下公開方法:
   	public Account(double initialBalance) //建構子,含初始餘額
   	public void credit(double amount) // 存款,含存款金額
   	public double getBalance() // 讀出餘額,回傳餘額
   測試時,可用建構子建立一個戶頭,初始餘額為50,先印餘額看對不對,
   再存入25,印餘額看對不對.

   註: 建構子若遇初始餘額<0,可一律設定為0.

BalicantaYao

package homework.week7;

public class Employee {
	
	private String firstName;
	private String lastName;
	
	public Employee(String firstName, String lastName) {
		this.firstName = firstName;
		this.lastName = lastName;

BalicantaYao

1. 接收使用者輸入的數，直到使用者輸入 -1 為止，並將使用者過去輸入的數，全部一起於一列印出，並用空白分開。
- Scanner, nextInt
- ArrayList - 使用者輸入的數字存在這
- 透過 for 印出

2. 電腦產生 7 個  1 - 42 的亂數，並不得重覆。
- Random
- HashSet

BalicantaYao

public boolean isValidEmailAddress(String email) {
       String ePattern = "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@((\\[[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\])|(([a-zA-Z\\-0-9]+\\.)+[a-zA-Z]{2,}))$";
       Pattern p = Pattern.compile(ePattern);
       Matcher m = p.matcher(email);
       return m.matches();
}

BalicantaYao

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<profiles version="13">
<profile kind="CodeFormatterProfile" name="Garmin" version="13">
<setting id="org.eclipse.jdt.core.formatter.insert_space_after_ellipsis" value="insert"/>
<setting id="org.eclipse.jdt.core.formatter.insert_space_after_comma_in_enum_declarations" value="insert"/>
<setting id="org.eclipse.jdt.core.formatter.insert_new_line_in_empty_annotation_declaration" value="insert"/>
<setting id="org.eclipse.jdt.core.formatter.insert_space_before_comma_in_allocation_expression" value="do not insert"/>
<setting id="org.eclipse.jdt.core.formatter.insert_space_before_at_in_annotation_type_declaration" value="insert"/>
<setting id="org.eclipse.jdt.core.formatter.parentheses_positions_in_for_statment" value="common_lines"/>
<setting id="org.eclipse.jdt.core.formatter.comment.new_lines_at_block_boundaries" value="true"/>