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public void p5() {
int i = 2540;
int[] check = {3, 4, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19};
boolean search = true;
while (search) {
boolean test = true;
for (int j = 0; j < check.length; j++) {
if (i % check[j] != 0) {
int n = 0, n1 = 2, n2 = 1, r = 2;
while (n < 4000000) {
n = n1 + n2;
if (n % 2 == 0) {
r += n;
}
n2 = n1; n1 = n;
int r = 0, a = 3, b = 5;
while (a < 1000 || b < 1000) {
r += a;
a += 3;
if (b < 1000 && (b % 3) != 0) {
r += b;
}
b += 5;
BUFF = (in[i:0..3] -> out[i] -> BUFF).
The same as saying...
BUFF = (in[0] -> out[0] -> BUFF
| in[1] -> out[1] -> BUFF
| in[2] -> out[2] -> BUFF
| in[3] -> out[3] -> BUFF).
Or you can use input parameters...
Inv = (1 / Det) * [d -b]
[-c a]
| 5 7| |-2 1 0|
A = |-3 2| B = | 5 9 -6|
That is to say the result of a 2x3 and 3x2 matrix will be a 3x3 matrix.
[3 5] [4 2 0] [17 36 40]
[6 1] * [1 6 8] = [25 18 8]
[1 3] [7 20 24]
However:
[4 2 0] [3 5] [24 22]
[1 6 8] * [6 1] = [47 35]
/**
* Adds two ints, x and y
* @param x An int to be added
* @param y The other int to be added
* @return Returns the sum of two ints, x and y
*/
public int add(int x, int y) {
return (x + y);
}
-- Dictionary to search
type Dict = [(String, String)]
dict :: Dict
dict = [("bread", "pain"),("milk", "lait"),("hello", "bonjour")]
-- Filter to apply to Dictionary
food :: [String]
food = ["bread", "milk"]
-- Where:
average :: Float -> Float -> Float -> Float
average x y z = (x + y + z) / 3