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function solution($A) { | |
// write your code in PHP7.0 | |
$values=array_count_values($A); | |
foreach($values as $key=>$value){ | |
if(($value % 2===1)){ | |
return $key | |
} | |
} |
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package main | |
import ( | |
"fmt" | |
) | |
func main() { | |
llist := &LinkedList{} | |
llist.Head = &Node{Data: 10} |
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public class Queue{ | |
private Node head; | |
private int length; | |
public void printQueue(){ | |
Node n=this.head; | |
while(n!=null){ | |
System.out.println(n.data+""); |
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public class Stack{ | |
private Node head; | |
//I Prefer this to having to walk the length of the stack everytime. | |
private int length=0; | |
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public class Node{ | |
int data; | |
Node next; | |
Node(int d){ | |
data=d; | |
} | |
} |
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package main | |
import "fmt" | |
func producer(p chan int, items int) { | |
defer close(p) | |
for i := 1; i <= items; i++ { | |
fmt.Println("Produer Producing ", i) | |
p <- i | |
} |
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func chanFib(n int, f chan int) { | |
fmt.Println("N is: ", n) | |
defer close(f) | |
i, j := 0, 1 | |
for { | |
temp := i + j | |
f <- i + j | |
j, i = i+j, j | |
if temp >= n { |
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