Lydon-01

public int yearsTilOneMillion(double initialBalance) {
    int year = 1;
    double savings = initialBalance;
    while (savings < 1000000){
        savings = savings * 1.05;
        year++;
    }
return year;
}

Lydon-01

/*
* find the biggest and smallest 
*/
public int findRange(int[] intArray) {
    if(intArray.length == 0){     //check that the array is bigger than 0
        return -1;
    }
    int largest = intArray[0]; 
    int smallest = intArray[0];
    for (int x=1;x<intArray.length;x++){ // find the smallest

Lydon-01

/* THIS IS BROKEN, NEEDS TO BE FIXED
* This question is taken from Udacity Lesson 4, Problem Set Question 8
*/

public class hello{
        public static void main(String[] args){
        roll();
		System.out.println(monopolyRoll());
		
		}

Lydon-01

## Python 2.7 
## GlueLastRunDuration.py 
## Version 1
## by Lydon Carter October 2018

## USE
# Script to get a specific AWS Glue Job and tell you the duration of
# the last run.
# Notes:
# -- The script will use the location you setup for your Glue Context in the "Needed stuff"

Lydon-01

import boto3

database_name = "databse"
table_name = "prefix-dir_name"
new_table_name = "more_awesome_name"

client = boto3.client("glue")
response = client.get_table(DatabaseName=database_name, Name=table_name)
table_input = response["Table"]
table_input["Name"] = new_table_name