RoyiAvital

Math Rendering Test Case

Inline Math

This is Inline Math using \( ... \) ( x + y = z \in \left{ -1, 1 \right} ) and now using $ ... $ $ x + y = z \in \left{ -1, 1 \right} $ and it should handle the case of giving my friend 2$.

We can also do the same without gaps.

This is Inline Math using \(...\) (x + y = z \in \left{ -1, 1 \right}) and now using $...$ $x + y = z \in \left{ -1, 1 \right}$ and it should handle the case of giving my friend 2$.

RoyiAvital