Shaddyjr

const x = 5;

x = 4;

console.log("Did you know? " + GodsOfDeathLoveApples);

Shaddyjr

All Secrets

Shaddyjr

{
    "base": {
        "Attack": 49,
        "Defense": 49,
        "HP": 45,
        "Sp.Atk": 65,
        "Sp.Def": 65,
        "Speed": 45
    },
    "name": "Bulbasaur",

Shaddyjr

def dirReduc(arr):
    directions = {
        "NORTH" : "SOUTH" , 
        "SOUTH" : "NORTH" , 
        "WEST" : "EAST" , 
        "EAST" : "WEST" 
    }
    
    for i in range(len(arr)-1):
        move      = arr[i]

Shaddyjr

# Quick test for skipping index within loop
nums = [1,2,3,4,5,6,7,8,9,10]

for i in range(len(nums)):
    print(i)
    num = nums[i]
    if(num % 2 == 0):
        i += 5
        
# Doh! prints 0-9

Shaddyjr

def dirReduc(arr):
    directions = {
        "NORTH" : "SOUTH" , 
        "SOUTH" : "NORTH" , 
        "WEST" : "EAST" , 
        "EAST" : "WEST" 
    }
    output = []
    i = 0
    while(i < len(arr)-1):

Shaddyjr

def dirReduc(arr):
    if(len(arr) <= 1): # short circuit
        return arr
    
    directions = {
        "NORTH" : "SOUTH" , 
        "SOUTH" : "NORTH" , 
        "WEST" : "EAST" , 
        "EAST" : "WEST" 
    }

Shaddyjr

# All credit to the following users on Code Wars:
# aenik97, CSNqwer, kickh, joei26, suhlob
opposite = {'NORTH': 'SOUTH', 'EAST': 'WEST', 'SOUTH': 'NORTH', 'WEST': 'EAST'}

def dirReduc(plan):
    new_plan = []
    for d in plan:
        if new_plan and new_plan[-1] == opposite[d]:
            new_plan.pop()
        else:

Shaddyjr

SELECT *
FROM actor AS a
INNER JOIN film_actor AS fa ON a.actor_id = fa.actor_id
INNER JOIN film       AS f  on f.film_id  = fa.film_id

Shaddyjr

-- https://stackoverflow.com/questions/11056235/finding-rows-with-same-values-in-multiple-columns
SELECT A.*
FROM YourTable A
INNER JOIN (SELECT Address, State
            FROM YourTable
            GROUP BY Address, State
            HAVING COUNT(*) > 1) B
ON A.Address = B.Address AND A.State = B.State