Shaddyjr

# source: https://www.hackerrank.com/challenges/piling-up/problem

def myFunction(sideLengths):
    curr_cube_length = float("inf")
    left_runner = 0
    right_runner = len(sideLengths) - 1

    while left_runner <= right_runner: # O(n)
        left_val  = sideLengths[left_runner]
        right_val = sideLengths[right_runner]

Shaddyjr

// Original TED Riddle Video: https://www.youtube.com/watch?v=YeMVoJKn1Tg

// check if number valid
function state_is_valid(array, two_found, ten_found){
    // whole number
    // not great than 60
    // no duplicates
    const last_num = array[array.length-1];
    const normal_check =  Math.floor(last_num) == last_num && last_num <= 60 && !has_duplicates(array);
    if(normal_check){

Shaddyjr

# source: https://www.hackerrank.com/challenges/down-to-zero-ii

#!/bin/python3

import os
import sys

MAX_N = 10 ** 6

# list of values by index, index corresponds to # of steps

Shaddyjr

// source: https://www.hackerrank.com/challenges/organizing-containers-of-balls
function organizingContainers(containers) {
    const n = containers.length;

    // keep # of balls per container
    const containerCounts = new Array(n).fill(0);
    // keep # of types of balls
    const ballTypes = new Array(n).fill(0);

    for(let i = 0; i < n; i++){

Shaddyjr

# source: https://leetcode.com/problems/combinations/

class Solution(object):
    def combine(self, n, k):
        output = []
        stack = []
        i = 1
        length = 0
        while True:
            # if stack if k long, add to solution (as copy)

Shaddyjr

// https://www.hackerrank.com/challenges/angry-professo
function angryProfessor(k, a) {
    // establishing constants
    const YES = "YES";
    const NO  = "NO";

    let inClassCount = 0; // keeping running total
    for(const arrivalTime of a){ // looping through each arrivalTime; O(n)
        inClassCount += arrivalTime <= 0; // get boolean (true/false) if student is late or on time, adding (1/0) to total
        if(inClassCount >= k) return NO; // before loop is done, if the total count is past threshold, stop and return NO

Shaddyjr

// source: https://www.youtube.com/redirect?q=https%3A%2F%2Fwww.hackerrank.com%2Fchallenges%2Fwaiter%2Fproblem%3Fh_r%3Dinternal-search&event=video_description&redir_token=QUFFLUhqbWRvZWVfbjJJUVQ0Q2J0WnpTLTVVUnBPYnFYd3xBQ3Jtc0trUXJ5MGF5UVJ5UlgxakpSQnZsXzB0QXY2bk5INzJ4MmhkRk5YLWUzV1RjLXQzX2xqUFl3LUtUVnhlT29QV0VoY3FhOVVqMDZrZ21JQjRXVEdvbUdHR3BZajllbmNuVGJBMTFtcXY0VWxaMGxyUmt1NA%3D%3D&v=UW-1KB9PFrA
// video: https://www.youtube.com/watch?v=UW-1KB9PFrA&lc=UgyNhlGoJNiMul7Byad4AaABAg
function getPrimes(n){
    const primesStr = "2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101,103,107,109,113,127,131,137,139,149,151,157,163,167,173,179,181,191,193,197,199,211,223,227,229,233,239,241,251,257,263,269,271,277,281,283,293,307,311,313,317,331,337,347,349,353,359,367,373,379,383,389,397,401,409,419,421,431,433,439,443,449,457,461,463,467,479,487,491,499,503,509,521,523,541,547,557,563,569,571,577,587,593,599,601,607,613,617,619,631,641,643,647,653,659,661,673,677,683,691,701,709,719,727,733,739,7

Shaddyjr

# source: https://www.hackerrank.com/challenges/kindergarten-adventures
# video: https://youtu.be/9vcrruySa9s
def sanitize_index(index, n):
    # index already valid
    if 0 <= index and index < n:
        return index
    
    # negative index
    if index < 0:
        return n + index

Shaddyjr

# source: https://www.hackerrank.com/challenges/gridland-metro
# video: https://youtu.be/H1Qbd652Oig

def gridlandMetro(n, m, k, tracks): # ALTERED NAME TO PLURAL 
    # tracks = [
    #    [row, col_start, col_end],
    #    ...
    # ]
    # sort by col start
    tracks.sort(key = lambda track: min(track[1], track[2])) # O(nlogn)

Shaddyjr

# source: https://www.hackerrank.com/challenges/lilys-homework
# video: https://youtu.be/HmyDuVZoE8Y
def lilysHomework_helper(arr, reverse = False):
    # clone arr, since modifying
    arr = arr[:] # O(n)?
    # arr = [2, 5, 3, 1]
    # store sorted array
    sorted_arr = sorted(arr, reverse = reverse) # O(nlogn)
    #    sorted_arr = [1, 2, 3, 5]
    #              OR [5, 3, 2, 1] if reverse = True