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October 2, 2017 07:31
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数学の問題の解答が一つだけしかないか確認
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| { | |
| "cells": [ | |
| { | |
| "cell_type": "markdown", | |
| "metadata": {}, | |
| "source": [ | |
| "## 問題\n", | |
| "ある自然数$x$がある.自然数$x$は$n,n+1(n\\leq200,n+1\\leq200)$を除く200以下の全ての自然数で割り切れるという性質を持つ.\n", | |
| "$n$,$n+1$の組をひとつ求めよ.\n", | |
| "\n", | |
| "## 回答\n", | |
| "1から200までの数の最小公倍数は,素因数分解すると奇数$k$を用いて$2^{7}k$という数字となる.ここで1から200までの数の最小公倍数を2と素数127で割った値を$y$とすると,$y$は127と128で割れない値になる.200以下の自然数に127以外に127の倍数はない.また$2^7$を素因数に持つ整数もない.よって$y$条件を満たす自然数$x$の条件を満たしている.よって$n,n+1$の組として(127,128)がある.\n", | |
| "\n" | |
| ] | |
| }, | |
| { | |
| "cell_type": "code", | |
| "execution_count": 23, | |
| "metadata": { | |
| "collapsed": false | |
| }, | |
| "outputs": [ | |
| { | |
| "name": "stdout", | |
| "output_type": "stream", | |
| "text": [ | |
| "succ: N=50,ans1=31,ans2=32,x=49984588778161237200\n", | |
| "failed: N=100\n", | |
| "succ: N=150,ans1=127,ans2=128,x=19541714063639443819857654528657219411089303003820795960456000\n", | |
| "succ: N=200,ans1=127,ans2=128,x=1327927515090260884407345538562367745796828278681721394601759928808007945120777126248000\n", | |
| "succ: N=250,ans1=127,ans2=128,x=130772114744924574706363590925874340043529225687091412695324636034906746054600753955764866241169244952000\n", | |
| "succ: N=300,ans1=256,ans2=257,x=17538359604668456465621738470710851838830797427977636846629028507364462353333899882243878603401973940799038401578085611825296000\n", | |
| "succ: N=350,ans1=256,ans2=257,x=15710940042837302532926587682318922297070523871850343852586835880017268131333200637890980421517484774745187218555684944617703292807701121816827184000\n", | |
| "succ: N=400,ans1=256,ans2=257,x=116085483413080851997297607751181984039505286682906734766771141886928415432271142595094870432957320402858350965325934882166692109947052808387473745418094345294247430032000\n", | |
| "succ: N=450,ans1=256,ans2=257,x=54729498379647217035756720098255511324480611519572358326125124530649666892630329064131208366027803043859696791877198220452470709974955328618693674871716693196945016675937982263864677908586448000\n", | |
| "succ: N=500,ans1=256,ans2=257,x=142489537585511374696233218908642604727162136675660037055154066215167913270046135008419766186559001916864421413712857734850805473372808048821619534365096893681053337667228401393490062686262540049514002346573676112000\n", | |
| "failed: N=550\n", | |
| "failed: N=600\n", | |
| "failed: N=650\n", | |
| "failed: N=700\n", | |
| "failed: N=750\n", | |
| "failed: N=800\n", | |
| "failed: N=850\n", | |
| "failed: N=900\n", | |
| "failed: N=950\n", | |
| "failed: N=1000\n" | |
| ] | |
| } | |
| ], | |
| "source": [ | |
| "\n", | |
| "\n", | |
| "def gcd(a,b):\n", | |
| " if a>b:\n", | |
| " return gcd(b,a)\n", | |
| " else:\n", | |
| " modula = b%a\n", | |
| " if modula == 0:\n", | |
| " return a\n", | |
| " else:\n", | |
| " return gcd(modula,a)\n", | |
| "\n", | |
| "def calc(N=200):\n", | |
| " flag = True\n", | |
| " \n", | |
| " for i in range(1,N+1):\n", | |
| " ans1 = i\n", | |
| " ans2 = i+1\n", | |
| " x = 1\n", | |
| " \n", | |
| " for j in range(1,N+1):\n", | |
| " if j == ans1 or j == ans2:\n", | |
| " pass\n", | |
| " else:\n", | |
| " a = gcd(x,j)\n", | |
| " x = x * j // a\n", | |
| " \n", | |
| " if x % ans1 == 0 or x % ans2 == 0:\n", | |
| " pass\n", | |
| " else:\n", | |
| " flag=False\n", | |
| " print(\"succ: N=%d,ans1=%d,ans2=%d,x=%d\" %(N,ans1,ans2,x))\n", | |
| " if flag:\n", | |
| " print(\"failed: N=%d\" % N)\n", | |
| "\n", | |
| "for i in range(1,21):\n", | |
| " calc(i*50)" | |
| ] | |
| } | |
| ], | |
| "metadata": { | |
| "kernelspec": { | |
| "display_name": "Python 2", | |
| "language": "python", | |
| "name": "python2" | |
| }, | |
| "language_info": { | |
| "codemirror_mode": { | |
| "name": "ipython", | |
| "version": 2 | |
| }, | |
| "file_extension": ".py", | |
| "mimetype": "text/x-python", | |
| "name": "python", | |
| "nbconvert_exporter": "python", | |
| "pygments_lexer": "ipython2", | |
| "version": "2.7.11" | |
| } | |
| }, | |
| "nbformat": 4, | |
| "nbformat_minor": 0 | |
| } |
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