anirudhjayaraman

## The problem could be written as u + 13v/w + x + 12y - z - 11 + pq/r -10 = 66
## which reduces to u + 13v/w + x + 12y - z + pq/r = 87
## This problem was solved on [1] "Wed May 27 17:46:52 2015"

baoloc <- function()
{
  packages <- rownames(installed.packages())
  if("combinat" %in% packages) library("combinat") else install.packages("combinat")
  numbers <- 1:9
  permutations <- permn(numbers) ## list of all permutations of vector input

anirudhjayaraman

[1] "The number of solutions are:"
[1] 128
         [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9]
solution    9    1    2    5    6    7    3    4    8
solution    7    9    6    1    5    2    3    4    8
solution    1    9    6    7    5    2    3    4    8
solution    1    5    2    3    4    8    7    9    6
solution    1    5    2    3    4    8    9    7    6
solution    5    1    2    9    6    7    3    4    8
solution    5    1    2    9    6    7    4    3    8

anirudhjayaraman

# set working directory to local directory where the data is kept
setwd("~/IGIDR/Development Economics - MIT/Homework Assignment 01")

# read the data
wb_dev_ind = read.csv("wb_dev_ind.csv")
# summarize data
summary(wb_dev_ind)

# Question 1
# What is the Mean of GDP per capita? What is the standard deviation of GDP per capita?

anirudhjayaraman

# Set working directory to local directory where the data is kept
setwd("~/IGIDR/Development Economics - MIT/Homework Assignment 02")
# read data
migueldata = read.csv("ted_miguel_worms.csv", header = TRUE)
attach(migueldata)
# Question 6
# How many observations are there per pupil? (Enter a whole number of 0 or higher)?
length(migueldata$pupid)
length(unique(migueldata$pupid))
# Question 7

anirudhjayaraman

def karatsuba(x,y):
	"""Function to multiply 2 numbers in a more efficient manner than the grade school algorithm"""
	if len(str(x)) == 1 or len(str(y)) == 1:
		return x*y
	else:
		n = max(len(str(x)),len(str(y)))
		nby2 = n / 2
		
		a = x / 10**(nby2)
		b = x % 10**(nby2)

anirudhjayaraman

procedure karatsuba(num1, num2)
  if (num1 < 10) or (num2 < 10)
    return num1*num2
  /* calculates the size of the numbers */
  m = max(size_base10(num1), size_base10(num2))
  m2 = m/2
  /* split the digit sequences about the middle */
  high1, low1 = split_at(num1, m2)
  high2, low2 = split_at(num2, m2)
  /* 3 calls made to numbers approximately half the size */

anirudhjayaraman

from string import *

# create decipher dictionary
l = letters[:26]
decipher = "".join([l[(i+3)%26] for i in range(len(l))])
decipher = dict(zip(decipher,l))

# open and read encrypted text
filename = 'estherDuflo.txt'
f = open(filename, 'rw')

anirudhjayaraman

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, Tih4i?|
,t| ih # L
W
Devwudfw
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uhfrug1 L hydoxdwh wkh hhfw ri wklv surjudp rq hgxfdwlrq dqg zdjhv e| frpelqlqj glhuhqfhv
dfurvv uhjlrqv lq wkh qxpehu ri vfkrrov frqvwuxfwhg zlwk glhuhqfhv dfurvv frkruwv lqgxfhg

anirudhjayaraman

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i?q|e r|i? ? t?_i?fq@d ,_f?rf rei4 @? k? q @* i*r)
, qfe4f?|
,q| fe # i
t
abstract
between 4<:6 and 4<:;/ the indonesian government constructed over 94/333 primar|
schools throughout the countr|1 this is one of the largest school construction programs on
record1 i evaluate the eect of this program on education and wages b| combining dierences
across regions in the number of schools constructed with dierences across cohorts induced

anirudhjayaraman

# Code for the merge subroutine

def merge(a,b):
    """ Function to merge two arrays """
    c = []
    while len(a) != 0 and len(b) != 0:
        if a[0] < b[0]:
            c.append(a[0])
            a.remove(a[0])
        else: