arthurio

data = ['a', 'b', 'c']

# Python v2.7
my_dict = {key: i for i, key in enumerate(data)}

# Python v2.6
my_dict = dict((key, i) for i, key in enumerate(data))

arthurio

PT.api.call('/bronto/referral', {
    method: 'post',
    data: {
        message: 'Example of message',
        emails: ['[email protected]', '[email protected]']
        // OR emails: '[email protected],[email protected]'
    },
    success: function (response) {
        console.log('OK');
    },

arthurio

import hmac
import hashlib
import simplejson
from time import time

data = {
    'timestamp': time(),
    'user': {
        'uid': 1234
    }

arthurio

{
    "timestamp": 1405631393.186916,
    "user": {
        "uid": "1234",
        "first_name": "John",
        "last_name": "Doe",
        "email": "[email protected]"
    },
    "transaction": {
        "id": "123-345-678"

arthurio

color wombat

hi ColorColumn ctermbg=lightgrey guibg=#474747

" Cursor shape
hi Cursor guibg=orange guifg=white

set autoindent
set smartindent
set tabstop=4

arthurio

'''
    Extends a dict object A with the properties of a dict object B.
    @param a: dict object
    @param b: dict object
'''
def extends(a, b):
    for key in b:
        if key in a:
            if isinstance(a[key], dict) and isinstance(b[key], dict):
                a[key] = extends(a[key], b[key])

arthurio

Keybase proof

I hereby claim:

• I am arthurio on github.
• I am arthurio (https://keybase.io/arthurio) on keybase.
• I have a public key ASCZuOqRvACWx0X4La-bIjFrt8FaUubXhRsM_zfRwpfGWAo

To claim this, I am signing this object:

arthurio

Setup

pip install pytest pydantic

Run

pytest

arthurio

#!/bin/zsh
set -euxo pipefail

for service in messaging-py
do
  (
    cd $service
    git clean -fd .
    mkdir $service
    mv .* * $service || true