azhai

#!/bin/bash

# Install parallel on CentOS 6.
# Assumes you are root. Prefix w/ sudo if not.

cd /etc/yum.repos.d/
#wget http://download.opensuse.org/repositories/home:tange/CentOS_CentOS-5/home:tange.repo
wget http://download.opensuse.org/repositories/home:/tange/CentOS_CentOS-6/home:tange.repo
yum install parallel

azhai

#-*- coding: utf-8 -*-

import os.path
import logging
from mlogging import FileHandler_MP, TimedRotatingFileHandler_MP
from functools import partial


class LevelFilter(logging.Filter):

azhai

/**
 * 开始的字符串相同
 *
 * @param string $haystack 可能包含子串的字符串
 * @param string $needle 要查找的子串
 * @return bool
 */
function starts_with($haystack, $needle)
{
    return strncmp($haystack, $needle, strlen($needle)) === 0;

azhai

<?php 
# 运行环境：PHP 5.4+ 

/* 100以内数字报数，5条规则参照https://www.jinshuju.net/f/EGQL3D */ 
function count_hundred($a, $b, $c) 
{ 
    assert ($a > 0 && $a < 10 
            && $b > 0 && $b < 10 
            && $c > 0 && $c < 10); 
    $numbers = range(1, 100); 

azhai

# -*- coding: utf-8 -*- 
# 运行环境：Python2.7 (Linux/Windows) 

""" 
题目给出的例子有错误，15——按题意规则5优先， 
应该输出Buzz而不是FizzBuzz 
好吧，我弄错，规则5只对第一个数字a起作用，那边更简单 
""" 

def count_hundred(a, b, c): 

azhai

#-*- coding:utf-8 -*-

from decimal import Decimal, getcontext
getcontext().prec = 50
PHI = Decimal(0.5) * (Decimal(5).sqrt() + 1)

def rdiff(n):
    n = Decimal(n)
    a = PHI * n
    return Decimal(round(a)) * n - a * n

azhai

#-*- coding:utf-8 -*-
"""
VIII  8
XDIX  99
"""

numerals = 'IVXLCDM'
numdict = dict(zip(numerals, range(len(numerals))))

def is_roman_number(number):

azhai

# -*- coding: utf-8 -*-
"""
给一组未排序的自然数，求其所有升序子序列的数量
Ex1:
给定5个数 3 1 2 5 4
结果为 8
[3],[1],[1,2],[1,2,5],[2],[2,5],[5],[4]
Ex2: 
给定20个数 1 5 4 3 7 8 9 10 2 19 17 11 12 13 14 15 20 16 6 18
结果为 48

azhai

#!/usr/bin/env php
<?php
# 运行环境：PHP 5.3+

/* 四个数字, 用四则运算和括号得到24 */
function calc24($a, $b, $c, $d)
{
    $nums = func_get_args();
    assert (is_int($a) && is_int($b) 
            && is_int($c) && is_int($d));

azhai

/etc/init.d/mysql stop
/etc/init.d/mysql start --skip-grant-tables

#回车输入空密码
mysql -u root -p

--执行SQL语句
UPDATE mysql.user SET Password=PASSWORD('my-new-password') WHERE User='root';
FLUSH PRIVILEGES;
quit;