Definition
flatten = lambda x: sum(x, [])Example usage
>>> flatten([[1,2],[3,4]])
[1, 2, 3, 4]| <!DOCTYPE html> | |
| <html> | |
| <head> | |
| <script type="text/javascript" src="https://unpkg.com/vue@next"></script> | |
| <script type="text/javascript" src="https://unpkg.com/[email protected]"></script> | |
| <script type="text/javascript" src="https://unpkg.com/[email protected]"></script> | |
| <title> Markdown </title> | |
| <style> | |
| html, |
| ;; roll-20-sided-dice.clj | |
| ;; return a function that rolls a 20 sided dice | |
| (def roll-20-sided-dice | |
| (fn [] (inc (int (rand 19))))) | |
| ;; call function to roll 20 sided dice | |
| (roll-20-sided-dice) |
| """ | |
| Random number guessing game | |
| """ | |
| import sys | |
| from random import randrange | |
| from math import ceil, floor | |
| class NumberGuessingGame: |
Definition
flatten = lambda x: sum(x, [])Example usage
>>> flatten([[1,2],[3,4]])
[1, 2, 3, 4]| # https://www.facebook.com/photo?fbid=3769368939762114&set=gm.1306912559653197 | |
| from itertools import chain | |
| import timeit | |
| # Interesting Code Sample | |
| # expected = [x for xs in [[x]*int(expected_dist[x]) for x in range(0, N+1)] for x in xs] | |
| # Original Appraoch |
| #!/usr/bin/env stack runhaskell | |
| -- getUser.hs | |
| import Data.Maybe | |
| import System.Environment | |
| main = do | |
| user <- lookupEnv "USER" | |
| print $ fromMaybe "" user |
| encrypt() { | |
| openssl aes-256-cbc -a -salt -in $1 -out $1.enc | |
| } | |
| decrypt() { | |
| openssl aes-256-cbc -d -a -in $1 -out $1.unlocked | |
| } | |
| #!/usr/bin/env python3 | |
| from argparse import ArgumentParser | |
| try: | |
| from googlesearch import search | |
| except ImportError: | |
| print("No module named 'google' found") | |
| def cli_args_string(parser = ArgumentParser()): |