codertcet111

Function Naive (T[0....n], P[0.....m])
{
  //This function is to find pattern P in the string T
  //Inputs are the two string T and P
  //Output will be the index of the matched position of T string
  for (i = 0, j = 0; to i <= n - m) do
  {
      if (T[i] == P[j]){
         temp_i = i
         while(pattern P matching with Text){

codertcet111

void radix(int array1[], int n){
 int buckets_container[10][10];  //This is the buckets shown in the diagram
 int count[10];                
 int numberOfIteration, largestNumber, div, bucketnumber, i, j, k;
 //Now FInd the largest number
 largestNumber = array1[0];
 for(i=1; i<n;i++)
  if (array1[i] > largestNumber)
   largestNumber = array1[i];
 

codertcet111

int factorial ( int n )
{
    if ( n == 0 )
        return 1;
    else
        return ( n * factorial ( n-1 ) );
}

codertcet111

int fibonacci ( int n )
{
    if ( n == 0 )
        return 0;
    if ( n == 1 )
        return 1;
    return ( fibonacci( n-1 ) + fibonacci( n-2 ) );
}

codertcet111

#include<stdio.h>
#include<conio.h>

void merge_sorting_function( int[], int, int);
void merge_with_sorting_function( int[], int, int, int);

void main(){
 
 //Here I have considered my own array u can replace it with actual code for accepting 
 // it from user

codertcet111

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if segue.identifier == "HistorySegue" {
            if let viewController = segue.destination as? HistoryController {
              if(barcodeInt != nil){
                viewController.detailItem = barcodeInt as AnyObject
               }
            }
        }
    }

codertcet111

#Here's a little help on delegates between two view controllers:

#Step 1: Make a protocol in the UIViewController that you will be removing/will be sending the data.
protocol FooTwoViewControllerDelegate:class {
    func myVCDidFinish(_ controller: FooTwoViewController, text: String)
}



#Step2: Declare the delegate in the sending class (i.e. UIViewcontroller)

codertcet111

students = {
  'Shubham': 'Expert in maths',
  'Ashwin': 'Expert in physics',
  'Sneha': 'Expert in Dance and Art'
  }

students['Ashwin']
# O/p:
'Expert in physics'

codertcet111

students = {
  Shubham: 'Expert in maths',
  Ashwin: 'Expert in physics',
  Sneha: 'Expert in Dance and Art'
  }

students[:Ashwin]
# O/p:
'Expert in physics'

codertcet111

hash1 = {a: 100, b: 200}
hash2 = {x: 'Shreya', y: 'Mohit'}

# Merging two hash, In this hash1 and hash2 won't change 
# only new hash will be generated by merging two hash
hash1.merge(hash2)
# O/P:
{:a=>100, :b=>200, :x=>"Shreya", :y=>"Mohit"}