balanced parentheses js solution

balanced parentheses

function isValid(s) {
    var stack = [];
    for (var i = 0; i < s.length; i++) {
        var c = s[i];
        if (c == '(' || c== '[' || c == '{') {
            stack.push(c);
            continue;
        }
        if (c == ')' || c== ']' || c == '}') {
            var l = stack.pop();
            if (
                (c == ']' && l == '[') ||
                (c == '}' && l == '{') ||
                (c == ')' && l == '(')
            ) {
                continue;
            }
            return false;
        }
    }
    return stack.length == 0
}