danvine

  def generate_secure_s3_url(s3_key)
    #
    # s3_key would be a path (including filename) to the file like:  "folder/subfolder/filename.jpg"
    # but it should NOT contain the bucket name or a leading forward-slash
    #
    # this was built using these instructions:
    # http://docs.amazonwebservices.com/AmazonS3/latest/dev/index.html?S3_QSAuth.html
    # http://aws.amazon.com/code/199?_encoding=UTF8&jiveRedirect=1
    
    s3_base_url       = MyApp::Application::S3_BASE_URL # i.e. https://mybucket.s3.amazonaws.com

danvine

# Runs a specified shell command in a separate thread.
# If it exceeds the given timeout in seconds, kills it.
# Returns any output produced by the command (stdout or stderr) as a String.
# Uses Kernel.select to wait up to the tick length (in seconds) between 
# checks on the command's status
#
# If you've got a cleaner way of doing this, I'd be interested to see it.
# If you think you can do it with Ruby's Timeout module, think again.
def run_with_timeout(command, timeout, tick)
  output = ''

danvine

var API_KEY = "XXX";
var SECRET_KEY = "XXX";
var crypto = require('crypto');

var url2png = function() {
	this.generateLink = function(url) {
		var options = "?url="+url + "&viewport=1480x1037&thumbnail_max_width=500";
		var token = crypto.createHash('md5').update(options + SECRET_KEY).digest('hex');

		return "http://api.url2png.com/v6/"+API_KEY+"/"+token+"/png/"+options;