daubattu

Keybase proof

I hereby claim:

• I am daubattu on github.
• I am daubattu (https://keybase.io/daubattu) on keybase.
• I have a public key ASBTpgg7GynCVrzIEtnznswkwvUA31GHj-Om_4ZCGZatrwo

To claim this, I am signing this object:

daubattu

function getTotalX(a, b) {
    // Write your code here
    let result = 0;
    let index = 1;
    let cloneA = a.splice(1, a.length); // clone new array of a but not a[0]
    while(a[0] * index <= b[0]) {
        if(
         cloneA.every(item => (a[0] * index) % item === 0)
          &&
          b.every(item => item % (a[0] * index) === 0)

daubattu

function breakingRecords(scores) {
    let best = 0;
    let worst = 0;
    let bestScore = scores[0];
    let worstScore = scores[0];
    const lengthOfData = scores.length;
    for(let i = 1; i < scores.length; i++) {
        if (scores[i] > bestScore) {
            bestScore = scores[i];
            best++;

daubattu

function birthday(s, d, m) {
    let result = 0;
    for(let i = 0; i < s.length - (m - 1); i++) {
        if (s.slice(i, i + m).reduce((r, v) => r + v, 0) === d) {
            result++;
        }
    }
    return result;
}

daubattu

function divisibleSumPairs(n, k, ar) {
	let result = 0;
	for(let i = 0; i < n - 1; i++) {
  	result += ar.slice(i + 1, n).filter((item, index) => {
    	if ((item + ar[i]) % k === 0) {
    		return item;
      }
    }).length;
  }
  return result;

daubattu

function bonAppetit(bill, k, b) {
    const sum = bill.reduce((r, v) => r + v, 0);
    const result = (sum - bill[k])/2;
    if (b - result === 0) console.log('Bon Appetit');
    else console.log(b - result);
}

daubattu

function pageCount(n, p) {
    /*
     * Write your code here.
     */
    const pageFromStart = Math.floor(p/2);
    const pageFromEnd = Math.ceil(((n % 2 !== 0 ? n - 1 : n) - p)/2);
    return Math.min(pageFromStart, pageFromEnd);
}

daubattu

function getMoneySpent(keyboards, drives, b) {
    /*
     * Write your code here.
     */
    let max = -1;
     
    for(let i = 0; i < keyboards.length; i++) {
        const keyboardPrice = keyboards[i];
        for(let j = 0; j < drives.length; j++) {
            const drivePrice = drives[j];

daubattu

const users = [
  {
    id: 1,
    name: 'Nguyễn Hưng Khánh',
    girl_friend: {
      name: 'Nguyễn Thị Khánh',
      address: 'Hà Nội'
    }
  },
  {

daubattu

// users[0]
console.log(users[0].girl_friend.name)

// users[1]
if (users[1].girl_friend) {
  console.log(users[1].girl_friend.name)
} else {
  console.log('Lêu lêu. Thằng này ê sắc ế')
}