Back to school Quiz (3-9) from Udacity Frond end developer

quizBack2school.js

/*
 * Programming Quiz: Back to School (3-9)
 */

// change the value of `education` to test your code
var education = "no high school diploma";

// set the value of this based on a person's education
var salary;

// your code goes here
switch (education) {
  case "no high school diploma": salary = 25636;
    break;
  case "a high school diploma": salary = 35256;
    break;
  case "an Associate's degree": salary = 41496;
    break;
  case "a Bachelor's degree": salary = 59124;
    break;
  case "a Master's degree": salary = 69732;
    break;
  case "a Professional degree": salary = 89960;
    break;
  case "a Doctoral degree": salary = 84396;
}

console.log("In 2015, a person with " + education
    + " earned an average of $" + salary.toLocaleString("en-US") + "/year.");

Revision 2 What Went Well

• Your code should have a variable education
• Your code should have a variable salary

What Went Wrong

• Your code is missing a switch statement
• Cannot read property '0' of null

Feedback: Not everything is correct yet, but you're close!

Revision 3 What Went Well

• Your code should have a variable education
• Your code should have a variable salary
• Your code should include a switch statement
• Your code should produce the expected output

Feedback: Your answer passed all our tests! Awesome job!

 /*
 * Programming Quiz: Back to School (3-9)
 */
// change the value of `education` to test your code
var education = "no high school diploma";
// set the value of this based on a person's education
var salary = 0;
// your code goes here
switch (education) {
    case "no high school diploma":
        salary = 25636;
        break;
    case "a high school diploma":
        salary = 35256;
        break;
    case "an Associate's degree":
        salary = 41496;
        break;
    case "a Bachelor's degree":
        salary = 59124;
        break;
    case "a Master's degree":
        salary = 69732;
        break;
    case "a Professional degree":
        salary = 89960;
        break;
    case "a Doctoral degree":
        salary = 84396;
        break;
  }
console.log ("In 2015, a person with " + education + " earned an average of $" + salary.toLocaleString("en-US") + "/year.");