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java.math.BigInteger.new(java.lang.String.new("\x00\x00\x00\x00\x00\x00\x00\x10").getBytes()).longValue() |
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grep -oP "Completed 200 OK in (\d+)ms" log/production.log | grep -oP "\d+" | |
# or, any request that spends at least 1ms on MassiveRecord: | |
cat log/production.log | grep -P "Completed 200 OK in (\d+)ms \(Views: \d+.\d+ms \| MassiveRecord: [1-9][0-9]?.\d+ms\)" | grep -oP "in \d+ms" | grep -oP "\d+" > ~/timings1.log |
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nmap <D-Up> :tabnew<CR> | |
nmap <D-Right> :tabnext<CR> | |
nmap <D-Left> :tabprevious<CR> | |
nmap <D-Down> :tabclose<CR> |
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sed -E '/^.$/d' |
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find . -size 0k -exec rm {} \; |
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def self.parse_ip(ip) | |
ip.split('.').collect(&:to_i).inject { |memo,x| x + (memo << 0x1) } | |
end |
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awk 'length($1) > length($2) {tmp = $2; $2 = $1; $1 = tmp} {print $0}' input.log > output.log |
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-- Facebook puzzle #1 - Hors d'oeuvres | |
-- http://www.facebook.com/careers/puzzles.php?puzzle_id=7 | |
output 0 = return () | |
output x = | |
putStrLn (gethop x) | |
output (x - 1) | |
gethop x | |
| div3 x && div5 x = "Hop\n" |
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