Drew Wyatt drewwyatt

Game Recommendations

This is a list of games I recommend checking out, I did my best to include a wide range of styles.

Here are the games I've gone into detail about below. They all have links to BGG where you can get more information, as well as a link to purchase them on Amazon. I believe these all satisfy the party-game-ish criteria (with one exception).

These link to my descriptions on this page (unless you are looking at this on an iPhone, then I think this table of contents doesn't actually work)

Pandemic Legacy (this is the exception)
Spyfall

	/* user nav
	================================================== */

	body.login nav.user {
	display: none!important;
	}

	/* hide the login on the login page ;-)*/
	nav.user {
	float: left;

	var albums = [];
	flickr.photosets.getList({ user_id: '127723465@N04' }, function(err, result) {
	result.photosets.photoset.forEach(function(set){
	albums.push({ id: set.id, title: set.title._content });
	});

	res.render('index', { title: 'Express', result: result, err: err, albums: albums });
	});

	import { Prompter, Validators } from './prompt';

	const main = async () => {
	const inputs = await new Prompter()
	.prompt('What is the auction id?', { validator: Validators.required })
	.then(p => p.prompt('Start Date?', { validator: Validators.isDate }))
	.then(p => p.prompt('End Date?', { validator: Validators.isDate }))
	.then(p => p.finish());

	console.log(inputs);

	/*
	[2018-12-17] Challenge #370 [Easy] UPC check digits
	The Universal Product Code (UPC-A) is a bar code used in many parts of the world. The bars encode a 12-digit number used to identify a product for sale, for example:

	042100005264
	The 12th digit (4 in this case) is a redundant check digit, used to catch errors. Using some simple calculations, a scanner can determine, given the first 11 digits, what the check digit must be for a valid code. (Check digits have previously appeared in this subreddit: see Intermediate 30 and Easy 197.) UPC's check digit is calculated as follows (taken from Wikipedia):

	1. Sum the digits at odd-numbered positions (1st, 3rd, 5th, ..., 11th). If you use 0-based indexing, this is the even-numbered positions (0th, 2nd, 4th, ... 10th).
	2. Multiply the result from step 1 by 3.
	3. Take the sum of digits at even-numbered positions (2nd, 4th, 6th, ..., 10th) in the original number, and add this sum to the result from step 2.

	╰─$ gitclean

	Running 'git fetch'...
	Running 'git remote prune origin'...
	Running 'git branch -vv'...
	Running 'git branch -d RN-423'...
	Running 'git branch -d WE-1885-cancel-subscription-reason'...
	Running 'git branch -d anna/WE-2304/app-page-refactor'...
	Running 'git branch -d chandra/we-2246-ts'...
	Running 'git branch -d dw-more-uat'...

	const handler = () => alert('🙌');
	const MyComponent = () => <button onClick={handler}>🔥</button>;

	const el = findDomNode(this);
	el.addEventListener("click", handler);

	/**
	* Summary of `ReactBrowserEventEmitter` event handling:
	*
	* - Top-level delegation is used to trap most native browser events. This
	* may only occur in the main thread and is the responsibility of
	* ReactDOMEventListener, which is injected and can therefore support
	* pluggable event sources. This is the only work that occurs in the main
	* thread.
	*
	* - We normalize and de-duplicate events to account for browser quirks. This

	import { useEffect, createRef } from 'react';

	const stopPropagationAndUseHandler = (handler: EventListener): EventListener => e => {
	e.stopImmediatePropagation();
	handler(e);
	}

	export const useNativeEvent = (type: string, handler: EventListener) => {
	const ref: React.RefObject<any> = createRef();