esrever10

1. 普通筛法  

	n = 1000000
	arr=[1]*(n+1)
	arr[0]=arr[1]=0
	s = 2
	for i in xrange(2,int(n**0.5)+1):
		if arr[i] == 1:
			for j in xrange(i*i, n+1,i):
				arr[j] = 0

esrever10

#include <algorithm>
#include <cstdio>
#include <queue>
#include <vector>
#include <cstring>
using namespace std;

//3个瓶子的大小
int ga[3] = {0};

esrever10

#include <algorithm>
#include <cstdio>
#include <queue>
#include <vector>
#include <cstring>
#include <set>
using namespace std;

class State {
public:

esrever10

#include <cstdio>
#include <vector>
#include <bitset>
#include <climits>
#include <iostream>
using namespace std;

#define MAX 15

vector<bitset<MAX> > vec;

esrever10

#!/usr/bin/python

# Quick and dirty demonstration of CVE-2014-0160 by Jared Stafford ([email protected])
# The author disclaims copyright to this source code.

import sys
import struct
import socket
import time
import select

esrever10

/* 
* CVE-2014-0160 heartbleed OpenSSL information leak exploit
* =========================================================
* This exploit uses OpenSSL to create an encrypted connection
* and trigger the heartbleed leak. The leaked information is
* returned encrypted and is then decrypted, decompressed and
* wrote to a file to annoy IDS/forensics. The exploit can set 
* the heatbeart payload length arbitrarily or use two preset 
* values for 0x00 and MAX length. The vulnerability occurs due 
* to bounds checking not being performed on a heap value which 

esrever10

#!/usr/bin/python

# Quick and dirty demonstration of CVE-2014-0160 by Jared Stafford ([email protected])

# Modified by Derek Callaway ([email protected]) to add STARTTLS protocols

# The authors disclaim copyright to this source code.

import sys
import struct

esrever10

/*
* CVE-2014-0160 heartbleed OpenSSL information leak exploit
* =========================================================
* This exploit uses OpenSSL to create an encrypted connection
* and trigger the heartbleed leak. The leaked information is
* returned encrypted and is then decrypted, decompressed and
* wrote to a file to annoy IDS/forensics.
*
* https://github.com/HackerFantastic/Public/blob/master/exploits/heartbleed.c
* https://raw.githubusercontent.com/decal/ssltest-stls/master/ssltest-stls.py

esrever10

I wasn't first to get the key. Nor was I second, third, or even fourth. I'm probably not even the
10th to get it (ok, looks like I was the 7th.) But I'm happy that I was able to prove to myself
that I too could do it.

First, I have to admit I was a skeptic. Like the handful of other dissenters, I had initially
believed that it would be highly improbable under normal conditions to obtain the private key
through exploiting Heartbleed. So this was my motivation for participating in Cloudflare's
challenge. I had extracted a lot of other things with Heartbleed, but I hadn't actually set out to
extract private keys. So I wanted to see first-hand if it was possible or not.

esrever10

#!/usr/bin/env python2
"""
Author: takeshix <[email protected]>
PoC code for CVE-2014-0160. Original PoC by Jared Stafford ([email protected]).

Supportes all versions of TLS and has STARTTLS support for SMTP,POP3,IMAP,FTP and XMPP.
"""

import sys,struct,socket
from argparse import ArgumentParser