eybisi

import base64
from Crypto.Cipher import AES

def stringdecrypt(a):
	string = base64.b64decode(a)
	iv = "@1B2c3D4e5F6g7H8"
	key = "\x34\x88\x6D\x5B\x09\x7A\x94\x19\x78\xD0\xE3\x8b\x1b\x5c\xa3\x29\x60\x74\x6a\x5e\x5d\x64\x87\x11\xb1\x2c\x67\xaa\x5b\x3a\x8e\xbf" #to 6a/5e for first iteration
	cleartext = AES.new(key[0:32], AES.MODE_CBC, iv).decrypt(string)
	return cleartext
 

eybisi

import base64
import sys

t = []
for i in range(256):
    t.append(i)
bArr = bytearray(sys.argv[1].encode("utf-8"))
i2 = 0

def swap(i,i2,arr):

eybisi

from idautils import *
from idaapi import *
from idc import *
from idautils import *
from types import *

def socksl(strinput,first_key,second_key):
    length = len(strinput)
    arr = [0 for i in range(length)]
    i = length - 1

eybisi

from idautils import *
from idaapi import *
from idc import *
from idautils import *
from types import *

def socksl(strinput,first_key,second_key):
    length = len(strinput)
    arr = [0 for i in range(length)]
    i = length - 1

eybisi

def socksl(strinput):
    length = len(strinput)
    arr = [0 for i in range(length)]
    i = length - 1
    while i >= 0:
        char1 = strinput[i]
        n = i - 1
        arr[i] = chr(ord(char1) ^ 0x5c)
        if n < 0:
            break

eybisi

import itertools

f = open("broken")
brokendata = f.read()
f.close()

head = 0x5ad
tail = 0x8d4

brokenhead = brokendata[0:head]

eybisi

setImmediate(function() { //prevent timeout
    console.log("[*] Starting script");

    Java.performNow(function() {

	     Java.choose("Draziw.Button.Mines.MainActivity", {
            onMatch: function (instance) {

eybisi

Keybase proof

I hereby claim:

• I am eybisi on github.
• I am eybisi (https://keybase.io/eybisi) on keybase.
• I have a public key ASCVtsAoUfJg_C8in2K1e50m9-PaweJ8wxkPmxzxcpNXiQo

To claim this, I am signing this object: