hai5nguy

import { dispatch } from '~/store/store'
import PadawanApi from '~/actions/padawan-api'


const create = async (student) => {
	dispatch({
		type: 'CREATE_STUDENT_START',
		student
	})

hai5nguy

const arr = [10, 12, 15, 21];
for (let i = 0; i < arr.length; i++) {
  setTimeout(function() {
    console.log('The index of this number is: ' + i);
  }, 3000);
} 
/////////////////////////////////
// example with the let keyword
/////////////////////////////////
// the following is how a computer will run the above for loop

hai5nguy

const arr = [10, 12, 15, 21];
for (let i = 0; i < arr.length; i++) {
  setTimeout(function() {
    console.log('The index of this number is: ' + i);
  }, 3000);
} 
/////////////////////////////////
// example with the let keyword
/////////////////////////////////
// the following is how a computer will run the above for loop

hai5nguy

const arr = [10, 12]; // for simplicity, let's only have 2 runs
for (let i = 0; i < arr.length; i++) {
  setTimeout(() => {
    console.log('The index of this number is: ' + i);
  }, 3000);
} 
// ///////////////////////////////
// example with the let keyword
// ///////////////////////////////
// the following is how a computer will run the above for loop

hai5nguy

var sampleArray = [[1,2,3],[[4],[5,6], [7,[8],9]], [10, 11], [12, [13, 14]]]

function flatten(array) {
    var result = [];
    recurseFlatten(array, result);;
    return result;
}

function recurseFlatten(array, result) {
    for (var i = 0; i < array.length; i++) {

hai5nguy

/**
 * You can brute force and increment/decrement the given number until you find a valid-all-even-digits
 * number, but the time complexity would be O(n) where n is value of the number.  Instead, you
 * can validate each digit starting with the highest power to come up with the nearest valid number.
 * Since you can make a number even by going up or down, both paths have to be considered.
 * 
 * For example, take 567;
 * 
 * It won't matter what you do with '67' because '5' will always be invalid.  So you have to make it even.