The bootcamp python file in ipnyb format

Python bootcamp assessment.ipynb

{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Starting with the inputs"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 43,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Enter the list of numbers as string:3 10 4 9 8 7 4\n"
     ]
    }
   ],
   "source": [
    "a = input('Enter the list of numbers as string:')"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 44,
   "metadata": {},
   "outputs": [],
   "source": [
    "a = a.split(' ')                     #spliting elements of the string"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 45,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "[3, 10, 4, 9, 8, 7, 4]"
      ]
     },
     "execution_count": 45,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "b = []                               #storing elements in a new list\n",
    "for strings in a:\n",
    "    b.append(int(strings))\n",
    "b"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 46,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Enter the required number as string:12\n"
     ]
    }
   ],
   "source": [
    "required_number = input('Enter the required number as string:')"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 47,
   "metadata": {},
   "outputs": [],
   "source": [
    "required_number = int(required_number)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 48,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "int"
      ]
     },
     "execution_count": 48,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "type(required_number)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Starting with the code"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 49,
   "metadata": {},
   "outputs": [],
   "source": [
    "b = list(set(b))   # eliminating duplicates"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 50,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "[3, 4, 7, 8, 9, 10]"
      ]
     },
     "execution_count": 50,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "b"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Demonstrating how to make pairs( could be done by itertools)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 54,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "3 4\n",
      "3 7\n",
      "3 8\n",
      "3 9\n",
      "3 10\n",
      "4 7\n",
      "4 8\n",
      "4 9\n",
      "4 10\n",
      "7 8\n",
      "7 9\n",
      "7 10\n",
      "8 9\n",
      "8 10\n",
      "9 10\n"
     ]
    }
   ],
   "source": [
    "for m in range(0,len(b)):                 \n",
    "    for n in range(m+1,len(b)):\n",
    "        print(b[m],b[n])        "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 53,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "[(3, 4),\n",
       " (3, 7),\n",
       " (3, 8),\n",
       " (3, 9),\n",
       " (3, 10),\n",
       " (4, 7),\n",
       " (4, 8),\n",
       " (4, 9),\n",
       " (4, 10),\n",
       " (7, 8),\n",
       " (7, 9),\n",
       " (7, 10),\n",
       " (8, 9),\n",
       " (8, 10),\n",
       " (9, 10)]"
      ]
     },
     "execution_count": 53,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "import itertools\n",
    "\n",
    "list(itertools.combinations(b, 2))"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 55,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "3 9\n",
      "4 8\n"
     ]
    }
   ],
   "source": [
    "for m in range(0,len(b)):\n",
    "    for n in range(m+1,len(b)):\n",
    "        if (b[m] + b[n] == required_number):\n",
    "            print(b[m],b[n])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
  }
 ],
 "metadata": {
  "kernelspec": {
   "display_name": "Python 3",
   "language": "python",
   "name": "python3"
  },
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
   "version": "3.6.4"
  }
 },
 "nbformat": 4,
 "nbformat_minor": 2
}