kerenskybr

#Given a list of lists t
flat_list = [item for sublist in t for item in sublist]

flat_list = []
for sublist in t:
    for item in sublist:
        flat_list.append(item)
        
# OR
flatten = lambda t: [item for sublist in t for item in sublist]

kerenskybr

# Given a list [[1,2,3], [4,5,6], [7,8,9]]

{words[0]:words[1:] for words in lst}

#result
#{1: [2, 3], 4: [5, 6], 7: [8, 9]}

kerenskybr

test_list = [{'gfg' : [1, 5, 6, 7], 'good' : [9, 6, 2, 10], 'CS' : [4, 5, 6]},
             {'gfg' : [5, 6, 7, 8], 'CS' : [5, 7, 10]},
             {'gfg' : [7, 5], 'best' : [5, 7]}]

# Concatenate Similar Key values
# Using loop
res = dict()
for dict in test_list:
    for list in dict:
        if list in res:

kerenskybr

from itertools import groupby

test_list = ['geek_1', 'coder_2', 'geek_4', 'coder_3', 'pro_3']

test_list.sort()

res = [list(i) for j, i in groupby(test_list,
                  lambda a: a.split('_')[0])]

#The original list is : [‘coder_2’, ‘coder_3’, ‘geek_1’, ‘geek_4’, ‘pro_3’]

kerenskybr

# Another way to populate a dict when using enumerate
my_dict = {}
my_string = 'Something'

for i, my_dict[i] in enumerate(my_string):
    pass
    
# Output:
# {0: 'S', 1: 'o', 2: 'm', 3: 'e', 4: 't', 5: 'h', 6: 'i', 7: 'n', 8: 'g'}