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For each product, find the customer that purchases the most
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select productCode as p, customerNumber as c from orders join orderdetails | |
on orders.orderNumber = orderdetails.orderNumber | |
group by productCode, customerNumber | |
having (productCode, customerNumber) = ( | |
select productCode, customerNumber | |
from orders join orderdetails ON orders.orderNumber = orderdetails.orderNumber | |
where productCode = p | |
group by productCode, customerNumber | |
order by sum(quantityOrdered) desc | |
limit 1 | |
) |
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select * from ( | |
select productCode, sum(quantityOrdered) as totalOrdered from orderdetails | |
group by productCode | |
) as t1 | |
JOIN ( | |
select productCode as p, customerNumber as c from orders join orderdetails | |
on orders.orderNumber = orderdetails.orderNumber | |
group by productCode, customerNumber | |
having (productCode, customerNumber) = ( | |
select productCode, customerNumber | |
from orders join orderdetails ON orders.orderNumber = orderdetails.orderNumber | |
where productCode = p | |
group by productCode, customerNumber | |
order by sum(quantityOrdered) desc | |
limit 1 | |
) | |
) as t2 | |
on t1.productCode = t2.p |
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