linstantnoodles

(*let A = [1;2;3]
 * genSublists A will yield
 * [[1]; [1; 2]; [1; 3]; [1; 2; 3];[2]; [2; 3]; [3]; []] *)

let rec gen list head =
    match list with
    [] -> []
    | first::rest -> let start = (head @ [first]) in
        let rec append list =
            match list with

linstantnoodles

(*checks for existence of (b,c)*)
let rec exists_bc(b,r) =
	match r with
	[] -> false
	| (x,c)::tail -> (x == b) || exists_bc(b,tail);;

(*constructs the list of relations that must exist for element a*)
let rec create_ac(a,b,r) =
	match r with
	[] -> []

linstantnoodles

//checks for existence of (b,c)
let rec exists_bc(b,r) =
	match r with
	[] -> false
	| (x,c)::tail -> (x == b) || exists_bc(b,tail);;

//constructs the list of relations that must exist for element a
let rec create_ac(a,b,r) =
	match r with
	[] -> []

linstantnoodles

/*
 * Question: Generate all the possible combinations of the letters on the telephone keypads. Recursively.
 * Basically, the product of N sets. 
 * e.g given 2,3. Valid combinations include (A,D),(A,E),(B,D)...
 */
public class KeyPadCombinations {
	/*
	 * Parameters 
	 * numbers = the key pad #s index = the position of a letter for
	 * each number level = the position of the current number

linstantnoodles

let rec unZip list =
    match list with
        [] -> ([], [])
        | (x, y)::rest ->
            let (xs, ys) = unZip rest in
                (x::xs, y::ys);;

linstantnoodles

(* The map function *)
let rec map fn list =
    match list with []->[]
    | n::ns -> fn n::map fn ns;;

(* The reduce function *)
let rec reduce fn id list =
    match list with []->id
    | n::ns->fn n (reduce fn id ns);;

linstantnoodles

(* Write a function val zip : 'a list * 'b list -> 'a * 'b list which accepts a 
* pair of lists of the same length and returns a list of pairs. For example,
* zip([1; 2; 3], ['A'; 'B'; 'C']) should return the list of pairs [(1, 'A'); (2,
* 'B'); (3, 'C')]. You may assume that the 2 input lists are of the same length.
* (2 Points)*)

let rec zip (a,b) =
  match (a,b) with
    ([],[]) -> []
    | ([],n::ns)-> []

linstantnoodles

var hash_table = {};

function check_dup(name){
    for(i = 0; i < name.length; i++){
        if(name[i] in hash_table){
            return false;
        }else{
            hash_table[name[i]] = true;                 
        }            
    }

linstantnoodles

function eu(a, b){
    if(a % b == 0){
        return b;                
    }else{
        return eu(b, a % b);
    }
}
alert(eu(30,12));