loneicewolf

for i in {1..3}
  do
    echo $i
    export m1="msg 1"
    export m2="msg 2"
    export m3="msg 3"

    case $i in
      1) echo "$m1";;

loneicewolf

#!/usr/bin/env bash
## https://stackoverflow.com/questions/10376206/what-is-the-preferred-bash-shebang

echo -e "THIS program: $0\n"
## cases.sh

# if $# (num. of inputs) is NOT(!) EQUALS TO(=) (so, !=) 2; print "argc IS NOT 2, ..."
if [ $# != 2 ]; then
    echo "argc IS NOT 2,  enter IP and PORT"
else

loneicewolf

/*
NOTE See Below for version 2 (and updates, erratas, fixes, links, and so on)
NOTE don't assume or think this is the latest because it's on first on top on the list; it's not.
Version 1 'naive approach' (hard coded values, etc)
gcc -g -o L1 lin_1.c
*/
#include <arpa/inet.h>
#include <stdio.h>
#include <unistd.h>
#define RP 1234

loneicewolf

import string

def find_position(char):
  for set_num in range(len(table)):
    if char in table[set_num]:
      return set_num
  return False

def forge_offsets(key, direction, offset):
  if type(key) is str:

loneicewolf

Keybase proof

I hereby claim:

• I am loneicewolf on github.
• I am william_martens (https://keybase.io/william_martens) on keybase.
• I have a public key ASAumSUfA1B43Z59IREVGt0bXq5NsKGgk5zb93pLhCfY8wo

To claim this, I am signing this object: