Created
December 19, 2012 16:46
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package main | |
import ( | |
"fmt" | |
"regexp" | |
) | |
var str string = `cpu 143074 414 36348 4569263 926 3 732 0 0 0 | |
cpu0 54787 108 14071 1114566 490 1 285 0 0 0 | |
cpu1 19898 16 4065 1165614 54 0 39 0 0 0 | |
cpu2 52089 234 14503 1117793 276 1 390 0 0 0 | |
cpu3 16298 56 3708 1171288 105 0 16 0 0 0` | |
func main() { | |
r, _ := regexp.Compile(`(?m)^(cpu\d+) (\d+)`) | |
m := r.FindAllStringSubmatch(string(str), -1) | |
fmt.Printf("%v\n", m) | |
for k, v := range m { | |
fmt.Printf("%d: %#v\n", k, v) | |
} | |
} | |
/* outputs: | |
[cpu0 54787 cpu1 19898 cpu2 52089 cpu3 16298] | |
0: "cpu0 54787" | |
1: "cpu1 19898" | |
2: "cpu2 52089" | |
3: "cpu3 16298" | |
*/ | |
/* want something like: | |
0: [["cpu0"] ["54787"]] | |
1: [["cpu1"] ["19898"]] | |
2: [["cpu2"] ["52089"]] | |
3: [["cpu3"] ["16298"]] | |
*/ | |
/* Found solution which is close enough: | |
0: []string{"cpu0 73674", "cpu0", "73674"} | |
1: []string{"cpu1 32192", "cpu1", "32192"} | |
2: []string{"cpu2 68983", "cpu2", "68983"} | |
3: []string{"cpu3 27855", "cpu3", "27855"} | |
*/ |
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