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package main

import (
	"bytes"
	"fmt"
	"io"
	"os/exec"
)

// RunAndListen intercepts cmd.Stdout and cmd.Stderr and runs cmd.

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Markdown style guide

Much of what makes Markdown great is the ability to write plain text, and get great formatted output as a result. To keep the slate clean for the next author, your Markdown should be simple and consistent with the whole corpus wherever possible.

We seek to balance three goals:

1. Source text is readable and portable.

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Does GitHub Markdown support trailing slash?

It does
not

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___________.__                   __                         ._.
\__    ___/|  |__ _____    ____ |  | __  ___.__. ____  __ __| |
  |    |   |  |  \\__  \  /    \|  |/ / <   |  |/  _ \|  |  \ |
  |    |   |   Y  \/ __ \|   |  \    <   \___  (  <_> )  |  /\|
  |____|   |___|  (____  /___|  /__|_ \  / ____|\____/|____/ __
                \/     \/     \/     \/  \/                  \/

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Chrome Infra Configuration service (luci-config)

• Owner: nodir@
• Prod instance: luci-config.appspot.com

[TOC]

Overview

• Stores a registry of projects (clients) and chrome infra services

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Uncaught SyntaxError: Unexpected token )
(index):28 GET http://githut.info/web/js/vendors/d3/d3.min.js (anonymous function) @ (index):28
main.js:1 Uncaught ReferenceError: d3 is not defined

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import java.util.*;
public class BellmanFord
{
    public static long dist[];
    public static long prev[];
    public static LinkedList<DirectedEdge> edgesList = new LinkedList<DirectedEdge>();
    
    public static class DirectedEdge{
        protected int v; 
        protected int w; // edge

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/*
Problem: given a long sequence of numbers, find those *two* that have odd number of occurrences. 
 
Limitations: 
* the sequence can be traversed only once 
* 10 KB of memory
*/

using System;
using System.Collections.Generic;

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package code;

public class MinWordRegion {
	public static class Result {
		/** zero-based */
		public int start;
		/** zero-based */
		public int end;
		
		public int length() {

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import random

def sort012(array):
  	n = len(array)
	p0 = 0 # end of the '0' block
	p2 = n - 1  # beginning of the '2' block

	i = 0
	while i <= p2:
		x = array[i]