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:g/pattern/d

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" Display context (5 lines) for all occurrences of a pattern.
:g/pattern/z#.5

" Same, but with some beautification.
:g/pattern/z#.5|echo "=========="

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/**
 * Sorts an array using the heapsort algorithm.
 * Heapsort is a comparison-based sorting algorithm.
 * Heapsort is an improved selection sort consisting of the use of a
 * heap data structure instead of a linear-time search to find the maximum or minimum element.
 *
 * @param {Array} arr - The array to be sorted.
 * @return {Array} - The sorted array.
 */
function heapsort(arr) {

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/**
 * Generates a list of strings based on the given integer input.
 *
 * @param  n  the maximum integer value to generate strings for
 * @return    a list of strings containing the generated values
 */
public List<String> fizzBuzz(int n) {
    List<String> res = new ArrayList<>(n)
    for (int i = 1; i <= n; i++) {
        StringBuilder sb = new StringBuilder()

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title	tags	excerpt	dateModified
JS Big-O Cheat Sheet	algorithm	Learn everything you need to know about Big-O notation with this handy cheatsheet.	2023-01-08 05:00:00 -0400

Definition

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let asciiValue: String = "1234567890ABCDEFGHIJ"

func asciiToHex(_ asciiValue: String) -> String {
    let chars: [String.Element] = Array(asciiValue)
    var hex: String = ""
    for char: String.Element in chars {
        hex += String(char.asciiValue!, radix: 16)
    }
    return hex
}

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// 17% faster than using filter on set

function difference(a, b) {
    const s = new Set(b)
    const result = []
    for (const x of a) {
        if (!s.has(x)) {
            result.push(x)
        }
    }

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/**
 * Check if a given string is a palindrome.
 *
 * @param {string} str - The string to be checked.
 * @return {boolean} Returns true if the string is a palindrome, false otherwise.
 */
function isPalindrome(str) {
    const formattedStr = str.toLowerCase().replace(/[\W_]/g, "");
    const reversedStr = formattedStr.split("").reverse().join("");
    return formattedStr === reversedStr;

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// This updated version should be more efficient due to the constant-time lookup in the dictionary, the use of StringBuilder for efficient string concatenation, and the iteration over the lookup keys in descending order.
func toRomanNumeral(_ num: Int) -> String {
    let lookup: [Int: String] = [
        1000: "M",
        900: "CM",
        500: "D",
        400: "CD",
        100: "C",
        90: "XC",
        50: "L",

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func isPangram(string: String) -> Bool {
    let alphabet = "abcdefghijklmnopqrstuvwxyz"
    let lowerCaseString = string.lowercased()
    
    for letter in alphabet {
        if !lowerCaseString.contains(letter) {
            return false
        }
    }