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using System; | |
using System.Collections.Generic; | |
using System.Linq; | |
using System.Net; | |
using System.Net.Sockets; | |
using System.Text; | |
using System.Threading; | |
using System.Threading.Tasks; | |
namespace ClientDemo |
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<script src="https://cdn.bootcss.com/mathjax/2.7.4/MathJax.js?config=default"> | |
MathJax.Hub.Config({ | |
tex2jax: { | |
inlineMath: [['$','$'],["\\(","\\)"]], | |
displayMath: [['\\[','\\]'], ['$$','$$']], | |
}, | |
}); | |
</script> |
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// Generated by gfwlist2pac | |
// https://github.com/clowwindy/gfwlist2pac | |
var domains = { | |
"stackoverflow.com": 1, | |
"w3schools.com": 1, | |
"codeforces.com": 1, | |
"disqus.com": 1, | |
"onedrive.live.com": 1, | |
"quora.com": 1, |
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def check(frame, p): | |
n = len(p) - 1 | |
fcs = frame[0: n] | |
for i in range(n, len(frame)): | |
fcs += frame[i] | |
fcs = bin(int(fcs, 2))[2:] | |
if (len(fcs) < len(p)): | |
continue | |
fcs = bin(int(fcs, 2) ^ int(p, 2))[2:] | |
while len(fcs) < n: |
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int findKthSmallest(int vec1[], int n1, int vec2[], int n2, int k) | |
{ | |
if (n1 == 0) | |
return vec2[k - 1]; | |
else if (n2 == 0) | |
return vec1[k - 1]; | |
if (k == 1) | |
return vec1[0] < vec2[0] ? vec1[0] : vec2[0]; | |
int idx1 = n1 * 1.0 / (n1 + n2) * (k - 1); |
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/** | |
* @author pwxcoo | |
* @email [email protected] | |
* @create date 2018-09-11 10:30:47 | |
* @modify date 2018-09-11 13:28:17 | |
* @desc LRU cache implemented by c++ | |
*/ | |
#ifndef _LRUCACHE_INCLUDED_ | |
#define _LRUCACHE_INCLUDED_ |
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def newtonSqrt(n, eps=1e-8): | |
""" | |
- ASSUME | |
f(x) = x^2 - n | |
when f(x)=0, x will be the root of n. | |
- DEDUCE BY Taylor Series Formula | |
f(x) = f(x0) + (x - x0)f'(x0) | |
- WHEN f(x)=0 | |
x = x0 - f(x0)/f'(x0) | |
x will be closer to the root than x0 |
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/** | |
* Time: O(n) | |
* Space: O(1) | |
* 1. find list if exists cycle. | |
* 2. 0 -> a(cycle s) -> b(cycle met) -> c(cycle s(e)) | |
* slow = a + b + (b + c)n1, fast = a + b + (b + c)n2. | |
* slow * 2 = fast | |
* 2a + 2b + 2*n1*(b + c) = a + b + n2*(b + c) => a = (n2 - 2*n1) * (b + c) - b | |
* After meeting, so one start going from head and meanwhile slow start going, they will meet at cycle begin. | |
**/ |
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vector<int> inorderTraversal(TreeNode* root) { | |
stack<TreeNode*> st; | |
vector<int> res; | |
auto now = root; | |
while(!st.empty() || now) | |
{ | |
while(now) | |
{ | |
st.push(now); |
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import java.util.concurrent.ExecutorService; | |
import java.util.concurrent.Executors; | |
import java.util.concurrent.atomic.AtomicInteger; | |
public class AtomicIntegerExample { | |
private AtomicInteger sycValue = new AtomicInteger(0); | |
private static final int MAX_SYC_VALUE = 3 * 10; |
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