rocktronica

<?php 
/*
Plugin Name: BubbleJax Wrapper
Plugin URI: http://bubblelifemedia.com/
Description: Name pending.
Author: Tommy
Version: 0.1
Author URI: http://bubblelifemedia.com/
*/

rocktronica

// Paste this into your JS console, love.

var sNeedle = prompt("Find what?").toLowerCase();
var tds = document.getElementsByClassName("default");
var iTdCount = tds.length;

for (var i = 0; i < iTdCount; i++) {
	var td = tds[i];
	var sHtml = td.innerHTML.toLowerCase();
	if (sHtml.indexOf(sNeedle) > -1) {

rocktronica

(function () {

// only run on IPs and browserling tunnel
if ((!!parseInt(location.host.replace(/\./g, ''), 10)) || (!!location.href.match('browserling'))) {

	// fake out DOM to get URL ports
	function getPort(sUrl) {
		var a = document.createElement("a");
		a.href = sUrl;
		return a.port;

rocktronica

javascript:(function(){window.onbeforeunload=function(){return '';}})();

rocktronica

data:text/html,Loading...<script>document.body.innerHTML=prompt("html?")</script>

rocktronica

javascript:(function(){location.search="?"+(+new Date());}())

rocktronica

var words = (function(){

	var sWords = document.body.innerText.toLowerCase().trim().replace(/[,;.]/g,'').split(/[\s\/]+/g).sort();
	var iWordsCount = sWords.length; // count w/ duplicates

	// array of words to ignore
	var ignore = ['and','the','to','a','of','for','as','i','with','it','is','on','that','this','can','in','be','has','if'];
	ignore = (function(){
		var o = {}; // object prop checking > in array checking
		var iCount = ignore.length;

rocktronica

data:text/html, <pre id="pre"></pre> <script> document.getElementById("pre").innerHTML = JSON.stringify( (function(s){ var s = (!!s.match(/\?/)) ? s.substr(s.indexOf("?")+1) : s; var qs = s.split("+").join(" "), params = {}, tokens, re = /[?&]?([^=]+)=([^&]*)/g; while (tokens = re.exec(qs)) { params[decodeURIComponent(tokens[1])] = decodeURIComponent(tokens[2]); } return params; } (prompt("?=?"))), null, 4 ); </script>

rocktronica

// Given a number, find the next higher number which has the exact same set of digits as the original number
// http://stackoverflow.com/questions/9368205/given-a-number-find-the-next-higher-number-which-has-the-exact-same-set-of-digi

function nextUp(iNumber){

	var sDigitsSorted = iNumber.toString().split('').sort().join('');

	var aPermutations = (function(){
		var i = parseInt(iNumber.toString().split('').sort().reverse().join(''),10) + 1,
			a = [];

rocktronica

(function(win, doc, body){

    var iCounter = 0, sUrl = doc.location.href, sTitle = doc.title || sUrl, 
        iMinutes = parseFloat(prompt("Seconds till refresh", "60"),10) || 60;
    
    doc.head.innerHTML = body.innerHTML = '';
    body.style.overflow = 'hidden';
    
    var iframe = win.iframe = doc.createElement("iframe");
    iframe.src = doc.location.href;