rodrigogiraoserrao

# https://mathspp.com/blog

from dataclasses import dataclass


@dataclass
class Cell:
    """Class that represents a Sudoku board cell."""

    row: int

rodrigogiraoserrao

class LogDict(dict):
    def __setitem__(self, key, value):
        print(f"Setting {key = } with {value = }")
        return super().__setitem__(key, value)
   
    def __getitem__(self, key):
        print(f"Getting {key = }")
        return super().__getitem__(key)

rodrigogiraoserrao

# A Tkinter calculator in a single Python *expression*
# See https://www.reddit.com/r/Python/comments/ojab0n/i_see_your_17_loc_calculator_and_i_raise_you_a/
(tk := __import__("tkinter")) and (bt_draw := lambda k, c, l: (bt := tk.Button(w, text=k, command=lambda: bt_press(k), width=6)) and bt.grid(column=c, row=l)) and (update := lambda t: d.config(text=t)) and (bt_press := lambda k: update("") if k == "C" else update(d["text"][:-1]) if k == "<" else update(str(round(eval(d["text"]), 6))) if k == "=" else update(d["text"] + k)) and (w := tk.Tk()) and w.title("TKalc") or (d := tk.Label(w, text="")) and d.grid(column=0, row=0, columnspan=5) or [bt_draw(k, n%4 + 1, n//4 + 1) for n, k in enumerate("()C<789/456*123-.0=+")] and w.mainloop()

rodrigogiraoserrao

\documentclass[11pt]{article}

\usepackage{fontspec}
\setmainfont{APL385 Unicode}
\setmonofont{APL385 Unicode}[Scale=MatchLowercase]

\begin{document}

I just want some ← +-×÷*⍟⌹○!? |⌈⌊⊥⊤⊣⊢ =≠≤<>≥≡≢ ∨∧⍲⍱ ↑↓⊂⊃⊆⌷⍋⍒ ⍳⍸∊⍷∪∩~ /\textbackslash⌿⍀ ,⍪⍴⌽⊖⍉ ¨⍨⍣.∘⍤⍥@ ⍞⎕⍠⌸⌺⌶⍎⍕ ⋄⍝→⍵⍺∇\& ¯⍬

rodrigogiraoserrao

⍝ PROBLEM 9.1, array-oriented solution, faster for the 3 examples provided.
Weights ← {
    (⎕IO ⎕ML ⎕WX) ← 0 1 3
    ⍝ Reads the mobile data from the file ⍵ and returns its weights.
    ⍝ Monadic function expecting a character vector and returning an integer vector.
    ⍝ Returns the weights ordered from left to right, top to bottom.

    ⍝ How it works:
    ⍝ We will build a square coefficient matrix where each variable is the weight of a left (┌) or right (┐) corner.
    ⍝ Let's say n is the number of leafs in the mobile; then n is also the number of pivots and by the lengths of the arms

rodrigogiraoserrao

:Namespace Mobiles
    ⍝ This namespace defines a set of helper functions for the recursive solution of the last problem.
    (⎕IO ⎕ML ⎕WX) ← 0 1 3 

    ⍝ Monadic function to take a path to a mobile.txt file and return a character matrix.
    OpenToMatrix ← {↑⊃⎕nget ⍵ 1}

    Parse ← {
        (⎕IO ⎕ML ⎕WX) ← 0 1 3 
        ⍝ Monadic function to parse (recursively) a mobile in matrix form.

rodrigogiraoserrao

⍝ PROBLEM 8.1
Balance ← {
    (⎕IO ⎕ML ⎕WX) ← 0 1 3
    ⍝ Given an integer vector ⍵, find a 2-partition with equal sums.
    ⍝ Monadic function expecting an integer vector.
    ⍝ This algorithm is O(2*≢⍵); we compute possible partitions of ⍵ and check
    ⍝  if their sums satisfy the requirement.
    ⍝ Return a 2-element vector of integer vectors.
    S ← 1⊥⍵     ⍝ Check simple necessary properties:
    2|S: ⍬      ⍝ odd sum can't be evenly split 

rodrigogiraoserrao

⍝ PROBLEM 7.1
⍝ Computes the check digit for a UPC-A barcode.
⍝ Monadic function expecting an 11-element integer vector.
⍝ Returns an integer. 
CheckDigit ← (10|∘-+.×∘(11⍴3 1))

⍝ Decimal repr of the right digits of a UPC-A barcode.
UPCRD ← 114 102 108 66 92 78 80 68 72 116            
⍝ Bit matrix with one right digit per row.
bUPCRD ← ⍉2∘⊥⍣¯1⊢ UPCRD

rodrigogiraoserrao

⍝ PROBLEM 6.1
Merge ← {
    (⎕IO ⎕ML ⎕WX) ← 0 1 3
    ⍝ Merges JSON data from a file named ⍵ into a template file named ⍺.
    ⍝ Dyadic function expecting a character vector on the left (template path) and a character vector on the right (data path).
    ⍝ Returns a character vector.
    t ← ⊃⎕NGET ⍺
    G ← (⎕JSON⊃⎕NGET ⍵)_SafeGet
    R ← {
        ⍝ Convert matched regex patterns into the appropriate replacements.

rodrigogiraoserrao

⍝ PROBLEM 5.1 
rr ← {
    (⎕IO ⎕ML ⎕WX) ← 0 1 3
    ⍝ Computes how much your investment is worth after cash flows and rate calculations.
    ⍝ Dyadic function expecting number vector on the left (deposits/withdrawals) and number vector on the right (corresponding rates).
    ⍝ At moment 1 you have r[1] ← ⍺[0] and at the subsequent moments you have r[n] ← ⍺[n-1] + r[n-1]×⍵[n-1].
    ⍝ Expanding the recurrence relation we can determine beforehand all expressions.
    ⍝ Assuming ⎕IO←0 and traditional mathematical notation,
    ⍝ r[1]←⍺[0], r[2]←⍺[1]+⍺[0]⍵[1], r[3]←⍺[2]+⍺[1]⍵[2]+⍺[0]⍵[2]⍵[1], r[4]←⍺[3]+⍺[2]⍵[3]+⍺[1]⍵[3]⍵[2]+⍺[0]⍵[3]⍵[2]⍵[1]
    ⍝ Returns a number.