sylvainpolletvillard

export const formatBytes = (precision = 2) => bytes => {
  if (typeof bytes !== "number") return bytes

  if (bytes === 0) return '0 Bytes';
  const k = 1024;
  const sizes = ['Bytes', 'KB', 'MB', 'GB', 'TB', 'PB', 'EB', 'ZB', 'YB'];

  const i = Math.floor(Math.log(bytes) / Math.log(k));

  return parseFloat((bytes / Math.pow(k, i)).toPrecision(precision)) + ' ' + sizes[i];

sylvainpolletvillard

const parseGrid = ([str]) => str
    .split('\n')
    .map(row => row.trim())
    .filter(row => row.length > 0)
    .map(row => row.split('').map(char => char !== '.'))

const formatGrid = (rows, ant) => rows
    .map((row, y) => row.map((cell, x) => {
        if (ant.x === x && ant.y === y) {
            return '8'

sylvainpolletvillard

function timer(delay){
    const subscribers = []
    let count = 0
    const interval = setInterval(() => {
        subscribers.forEach(observer => observer.next(count))        
        count++;
    }, delay)

    const timerObservable = {
        subscribe: observer => {

sylvainpolletvillard

/*
Given a string str and a dictionary dict containing a list of non-empty words, add spaces in str to construct a “sentence” where each word is a valid word in dict. Return all possible sentences. You are allowed to reuse the words in dict.

Example:
str = “penpineapplepenapple”
dict = [“apple”, “pen”, “applepen”, “pine”, “pineapple”]
$ makeSentence(str, dict) $ [ “pen pine apple pen apple”, “pen pineapple pen apple”, “pen pine applepen apple” ]
*/
function makeSentence(str, dict){
  const findWordsAtStart = str => dict.filter(word => str.startsWith(word))