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/**
 * @param {string[]} operations
 * @return {number}
 */
var finalValueAfterOperations = function(operations) {
    // Step 1: Initialize the variable X to 0
    let X = 0;

    // Step 2: Loop through each operation in the array
    for (let i = 0; i < operations.length; i++) {

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/**
 * @param {string} s
 * @param {number} a
 * @param {number} b
 * @return {string}
 */
var findLexSmallestString = function(s, a, b) {
    // Set to keep track of visited strings to avoid revisiting the same state
    const visited = new Set();

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/**
 * Calculates the maximum number of partitions after performing operations
 * that allow up to `k` distinct characters per partition.
 *
 * @param {string} s - Input string consisting of lowercase letters.
 * @param {number} k - Maximum number of distinct characters allowed per partition.
 * @return {number} - Maximum number of partitions achievable.
 */
var maxPartitionsAfterOperations = function(s, k) {
    const n = s.length;

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/**
 * @param {number[]} nums
 * @param {number} value
 * @return {number}
 */
var findSmallestInteger = function(nums, value) {
    // Step 1: Create a frequency map to count how many times each remainder appears
    const freq = new Map();

    for (let num of nums) {

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/**
 * @param {number[]} nums
 * @return {number}
 */
var maxIncreasingSubarrays = function (nums) {
    let maxK = 0;       // Stores the maximum valid k found so far
    let curLen = 1;     // Length of the current strictly increasing run
    let prevLen = 0;    // Length of the previous strictly increasing run

    for (let i = 1; i < nums.length; i++) {

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/**
 * @param {number[]} nums
 * @param {number} k
 * @return {boolean}
 */
var hasIncreasingSubarrays = function(nums, k) {
    // Helper function to check if a subarray is strictly increasing
    function isStrictlyIncreasing(start, end) {
        for (let i = start; i < end; i++) {
            if (nums[i] >= nums[i + 1]) {

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/**
 * @param {string[]} words
 * @return {string[]}
 */
var removeAnagrams = function(words) {
    // Helper function to check if two words are anagrams
    const isAnagram = (word1, word2) => {
        // Sort the letters of both words and compare
        return word1.split('').sort().join('') === word2.split('').sort().join('');
    };

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/**
 * @param {number} m
 * @param {number} k
 * @param {number[]} nums
 * @return {number}
 */
var magicalSum = function(m, k, nums) {
    const MOD = BigInt(1e9 + 7); // Modulo for large number arithmetic
    const n = nums.length;

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/**
 * @param {number[]} power
 * @return {number}
 */
var maximumTotalDamage = function(power) {
    // Step 1: Count how many times each damage value appears
    const count = new Map();
    for (const dmg of power) {
        count.set(dmg, (count.get(dmg) || 0) + 1);
    }

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/**
 * @param {number[]} energy
 * @param {number} k
 * @return {number}
 */
var maximumEnergy = function(energy, k) {
    // Initialize the answer to a very low number to ensure any valid energy path will be higher
    let ans = -1e99;

    // Try starting from each index i in the range [0, k)