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/**
 * This function calculates the minimum operations required to satisfy certain conditions.
 * @param {number[]} nums - Array of numbers to process.
 * @param {number} k - Threshold value to compare against.
 * @return {number} - Returns the size of the unique set of numbers greater than k, or -1 if any number is less than k.
 */
var minOperations = function (nums, k) {
    // Check if any number in the array is less than k. If so, return -1.
    for (let num of nums) {
        if (num < k) return -1;

tatsuyax25

/**
 * Finds the minimum number of operations required to make all elements in the array distinct
 * by removing groups of 3 elements from the start of the array.
 *
 * @param {number[]} nums - The input array of integers.
 * @return {number} - The minimum number of operations required.
 */
var minimumOperations = function(nums) {
    // Create an array to track the elements that have already appeared
    let appeared = new Array(101); // This seems to assume the numbers are in the range [0, 100].

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/**
 * Determines if the given array of numbers can be partitioned into two subsets with equal sum.
 * @param {number[]} nums - Array of integers
 * @return {boolean} - True if the array can be partitioned, otherwise false
 */
var canPartition = function(nums) {
    const total = nums.reduce((a, b) => a + b, 0);

    // If the total is odd, partitioning into two equal subsets is not possible
    if (total % 2 !== 0) return false;

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/**
 * Finds the largest subset of numbers from `nums` such that every pair (i, j) 
 * in the subset satisfies:
 * nums[i] % nums[j] === 0 or nums[j] % nums[i] === 0.
 *
 * @param {number[]} nums - Array of distinct positive integers.
 * @return {number[]} - The largest divisible subset.
 */
var largestDivisibleSubset = function(nums) {
    // Edge case: If the input is empty, return an empty subset.

tatsuyax25

/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root

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/**
 * @param {number[]} nums
 * @return {number}
 */
var maximumTripletValue = function(nums) {
     const n = nums.length;
    if (n < 3) return 0; // Edge case: no valid triplet possible

    // Arrays to store the maximum values
    const leftMax = new Array(n).fill(Number.MIN_SAFE_INTEGER);

tatsuyax25

/**
 * @param {number[]} nums
 * @return {number}
 */
var maximumTripletValue = function(nums) {
    // Initialize the maximum value to 0 (default if all values are negative)
    let maxValue = 0;

    // Outer loop: Fix the first index i
    for (let i = 0; i < nums.length - 2; i++) {

tatsuyax25

/**
 * Function to calculate the maximum points that can be earned
 * by answering questions strategically.
 * @param {number[][]} questions - Array of questions, where each question is represented as [points, brainpower].
 * @return {number} - The maximum points that can be achieved.
 */
var mostPoints = function(questions) {
    const n = questions.length;
    
    // Memoization array to store results of subproblems

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/**
 * Calculates the difference between the maximum and minimum scores
 * of distributing marbles into k bags based on given rules.
 *
 * @param {number[]} weights - Array representing the weights of marbles.
 * @param {number} k - Number of bags to divide the marbles into.
 * @return {number} - Difference between the maximum and minimum scores.
 */
var putMarbles = function(weights, k) {
    // If there's only one bag, no need to calculate; the difference is 0.

tatsuyax25

// Function to get the index of a character in the alphabet (0 for 'a', 1 for 'b', etc.)
const getIndexCharacter = (c) => {
    return c.charCodeAt(0) - 'a'.charCodeAt(0);
}

/**
 * Function to partition the string into as many parts as possible
 * such that each character appears in at most one part.
 * 
 * @param {string} s - Input string