techsin

eRESUME

Muhammad UMER

Fullstack Developer Email:​ ​[email protected] Linkedin:​ ​https://www.linkedin.com/in/muhammadumerdev/ Stackoverflow:​ ​https://stackoverflow.com/users/1319799/muhammad-umer Github:​ ​https://github.com/techsin

techsin

function sortBooks() {
    let books = [...document.querySelectorAll('ul#g-items li h3> a.a-link-normal')].map(el => findAncestor(el, 'g-item-sortable'));
    let sorted = bubbleSort(books);
    let frag = document.createDocumentFragment();
    sorted.forEach(x => frag.appendChild(x));
    let ul = document.querySelector("ul#g-items");
    ul.innerHTML = '';
    ul.append(frag);
    alert('done');
    return frag

techsin

function merc(lat, lon) {
    let r_major = 6378137.000,
    x = r_major * toRadians(lon),
    scale = x/lon,
    y = 180.0/Math.PI * Math.log(Math.tan(Math.PI/4.0 + lat * (Math.PI/180.0)/2.0)) * scale;
    return (x, y)
}

function toRadians (angle) {
  return angle * (Math.PI / 180);

techsin

const crypto = require('crypto');
function hash(msg){
    return crypto.createHash('sha256').update(msg).digest('hex');
}

// '24d78aedae3a0747299d9c7b93f524221aa20c73274faab1ef75f584c453fcb0'
// what did i say?

techsin

var arr = ["apple", ["apple","fix","apple"],["Apple", "apple"]];


function recurCount([...arr]) {
  const WORD = 'apple';
  
  if (arr.length === 0) {
    return 0;
  } else {
    let tmp = arr.pop();

techsin

function isThere(arr, t) {
	//Usually Mergesort	n log(n)
  arr.sort((a,b)=> a>b?true:false);
	
	let i = 0, 
		j = arr.length-1,
		x = arr[i], 
		y = arr[j];
	
  // O(n)

techsin

socket.emit('message', "this is a test"); //sending to sender-client only
socket.broadcast.emit('message', "this is a test"); //sending to all clients except sender
socket.broadcast.to('game').emit('message', 'nice game'); //sending to all clients in 'game' room(channel) except sender
socket.to('game').emit('message', 'enjoy the game'); //sending to sender client, only if they are in 'game' room(channel)
socket.broadcast.to(socketid).emit('message', 'for your eyes only'); //sending to individual socketid
io.emit('message', "this is a test"); //sending to all clients, include sender
io.in('game').emit('message', 'cool game'); //sending to all clients in 'game' room(channel), include sender
io.of('myNamespace').emit('message', 'gg'); //sending to all clients in namespace 'myNamespace', include sender
socket.emit(); //send to all connected clients
socket.broadcast.emit(); //send to all connected clients except the one that sent the message

techsin

/*
Question 1 -- sumOfTwo(a,b,v): You have two integer arrays, a and b, and an integer target value v. Determine whether there is a pair of numbers, where one number is taken from a and the other from b, that can be added together to get a sum of v. Return true if such a pair exists, otherwise return false.

Question 2 -- stringReformatting(string): The string s contains dashes that split it into groups of characters. You are given an integer k that represents the number of characters in groups that your output should have. Your goal is to return a new string that breaks s into groups with a length of k by placing dashes at the correct intervals. If necessary, the first group of characters can be shorter than k. It is guaranteed that there are no consecutive dashes in s. 

For s = "2-4a0r7-4k" and k = 4, the output should be stringReformatting(s, k) = "24a0-r74k"; 

The input string "2-4a0r7-4k" is split into three groups with lengths of 1, 5 and 2. Since k = 4, you need to split the string into two groups of

techsin

var max = 20;
var i = 0;
   var word;
   while (i++ < max) {
       if (i % 3 == 0) {
           word = 'Fizz';
           if (i % 5 == 0) {
               word += 'Buzz';
           }
       } else if (i % 5 == 0) {

techsin

.widget .header h3 { 
  padding:30px!important;
  color: green!important;
  background-color: black!important;
  font-size:30px!important;
  text-align: center!important;
}