thehappybug

Keybase proof

I hereby claim:

• I am thehappybug on github.
• I am jaffery (https://keybase.io/jaffery) on keybase.
• I have a public key whose fingerprint is 6C1C 542A D207 8027 BB55 578B A59D A383 F38D 48FB

To claim this, I am signing this object:

thehappybug

curl 'https://demo.api-platform.com/books' \
  -H  'accept: application/json'

thehappybug

npm update react react-dom @types/react @types/react-dom

thehappybug

import * as React from 'react';

interface AppContextInterface {
  name: string,
  author: string,
  url: string
}

const {Provider, Consumer} = React.createContext<AppContextInterface>();

thehappybug

import * as React from 'react';

interface AppContextInterface {
  name: string,
  author: string,
  url: string
}

const {Provider, Consumer} = React.createContext<AppContextInterface | null>(null);

thehappybug

import * as React from 'react';

export interface AppContextInterface {
  name: string,
  author: string,
  url: string
}

const ctxt = React.createContext<AppContextInterface | null>(null);

thehappybug

import * as React from 'react';
import { AppContextInterface, AppContextProvider } from './AppContext';

const sampleAppContext: AppContextInterface = {
  name: 'Using React Context in a Typescript App',
  author: 'thehappybug',
  url: 'http://www.example.com'
};

export const App = () => (

thehappybug

import * as React from 'react';
import { AppContextConsumer } from './AppContext';

export const PostInfo = () => (
  <AppContextConsumer>
    {appContext => appContext && (
      <div>
        Name: {appContext.name},
        Author: {appContext.author},
        Url: {appContext.url}

thehappybug

<AppContextConsumer>
  {appContext => ...}
</AppContextConsumer>

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type Omit<T, K extends keyof T> = Pick<T, Exclude<keyof T, K>>;

export function withAppContext<
  P extends { appContext?: AppContextInterface },
  R = Omit<P, 'appContext'>
  >(
  Component: React.ComponentClass<P> | React.StatelessComponent<P>
  ): React.SFC<R> {
  return function BoundComponent(props: R) {
    return (