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function eventAll(eventName) {
    // https://support.google.com/analytics/answer/1033068?hl=en
    // non_interaction/nonInteraction to avoid raising bounce rate
    // when there's an event that fires every page load.
    if (window.gtag) {
        gtag('event', eventName, {
            non_interaction: true,
        });
    } else if (window.ga) {
        ga('send', {

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// Paste the following into your js console while viewing images, e.g. on your facebook feed.
// It will show the "alt" attributes that facebook assigned your images.
// It's an interesting peek into how facebook analyzes your images.

setInterval(function() {
    var imgs = document.querySelectorAll("img");
    for (var i = 0; i < imgs.length; i++) {
        var alt = imgs[i].alt;
        if (alt && !imgs[i].getAttribute("alted")) {
            var div = document.createElement("div");

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// An example race condition in JavaScript
// When you run this script using Node or in a browser, you'll find it
// does not print "Ended with 0", but a random number. Even though the functions running
// simply loop 100 iterations of adding and subtracting. The reason the end result is random
// is because the sleeps are of random duration and the time between the read of the variable
// causes the eventual write to be incorrect when `adder` and `subber` interleave.
// This problem is similar to https://en.wikipedia.org/wiki/Time-of-check_to_time-of-use

let number = 0;
const times = 100;

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// E.g used on
// https://www.crunchbase.com/search/principal.investors/8ff469dfad43f418bb327da3508ebddf
// Crunchbase hides search results behind a darker element and blurs the rows. This removes that
// so you can see the top 15 results instead of just 5. Though you won't be able to see beyond that.
document.querySelector('.all-results-upsell-wrapper').remove()
document.querySelectorAll('grid-row').forEach((it) => { it.setAttribute("class", "") })

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import glob
import os

unknown_location_acronym = 'tbd'

# https://gist.github.com/rogerallen/1583593
us_state_to_abbrev = {
    'Alabama': 'AL',
    'Alaska': 'AK',
    'American Samoa': 'AS',

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/*
From 2020-11-29 [email protected] newsletter challenge

Given an array of integers and a target value, return the number of pairs of array 
elements that have a difference equal to a target value.


Examples:
$ arrayDiff([1, 2, 3, 4], 1)
$ 3 // 2 - 1 = 1, 3 - 2 = 1, and 4 - 3 = 1

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javascript: function findNodes(el) {
    return el.querySelectorAll('#metadata-line');
}

function isDigit(str) {
    return str.length === 1 && str.match(/[0-9]/i);
}

function metricVal(el) {
    let modifiers = {

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"""
The Simplest Math Problem No One Can Solve - YouTube - https://www.youtube.com/watch?v=094y1Z2wpJg
Collatz Conjecture

3x + 1
x / 2


(3x + 1) / 2 = 1.5x + 0.5
3(x/2) + 1 = 1.5x + 1

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// The Simplest Math Problem No One Can Solve
// https://www.youtube.com/watch?v=094y1Z2wpJg
// https://en.wikipedia.org/wiki/Collatz_conjecture
// I'm looking for loops by checking every positive integer (1, 2, 3...)
// and I'm using the binary representation (0b0, 0b10, 0b11, 0b100, ...)
// as an up and down path of a collatz loop where '1' means (3x+1)/2 and 
// '0' means x/2 . `frac_follow_path` calculates what should be the starting
// value based on that collatz loop path, and if that's an integer - 
// we found a loop.
// Problems so far:

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dateEls = [...document.querySelectorAll('relative-time')]
dates = dateEls.map(it => new Date(it.attributes['datetime'].textContent));
durations = [];
for (const [i, dt] of dates.entries()) {
  const hours = Math.round((dates[i] - dates[i + 1]) / 3600e2) / 10;
  const newNode = document.createTextNode("- took hours " + hours);
  dateEls[i].parentNode.appendChild(newNode);
  durations.push(hours)
}