vijfhoek

/* Generated by           cobc 3.1.2.0 */
/* Generated from         day06b.cob */
/* Generated at           nov 06 2021 23:45:03 */
/* GnuCOBOL build date    Dec 24 2020 19:08:58 */
/* GnuCOBOL package date  Dec 23 2020 12:04:58 UTC */
/* Compile command        cobc -C day06b.cob */

#include <stdio.h>
#include <string.h>
#define  COB_KEYWORD_INLINE __inline

vijfhoek

       identification division.
       program-id. day06.
       
       data division.
       working-storage section.
       01 input-line pic x(100).

       01 action pic x(10).
       01 coords pic x(100).
       01 start-coords pic x(100).

vijfhoek

       identification division.
       program-id. day06.
       
       data division.
       working-storage section.
       01 input-line pic x(100).

       01 action pic x(10).
       01 coords pic x(100).
       01 start-coords pic x(100).

vijfhoek

       identification division.
       program-id. aoc03part1.
       
       data division.
       working-storage section.
       01 ws-input pic x(10000).
       01 ws-char pic x.
       01 ws-i pic 9(10) value 1.

      *Initialize 3-digit numerics for the x and y coordinates

vijfhoek

       identification division.
       program-id. aoc03part1.
       
       data division.
       working-storage section.
       01 ws-input pic x(10000).

       01 ws-char  pic x.
       01 ws-i     pic 9(10).

vijfhoek

Keybase proof

I hereby claim:

• I am vijfhoek on github.
• I am vijfhoek (https://keybase.io/vijfhoek) on keybase.
• I have a public key ASD-bW3fCSNln1L6UoxMw2XRDcg-Cye3eAhzQe-ShnLVTwo

To claim this, I am signing this object:

vijfhoek

TIMx->PSC = 47;
TIMx->ARR = 8;
TIMx->CCR1 = 4;
TIMx->CCMR1 |= TIM_CCMR1_OC1M_2 | TIM_CCMR1_OC1M_1 | TIM_CCMR1_OC1PE;
TIMx->CCER |= TIM_CCER_CC1E;
TIMx->BDTR |= TIM_BDTR_MOE;
TIMx->CR1 |= TIM_CR1_CEN;
TIMx->EGR |= TIM_EGR_UG;

vijfhoek

from typing import Tuple

def rule_0(s):
    if s != '':
        v0 = rule_8(s)
        v1 = (out for inp in v0 for out in rule_11(inp))
        yield from v1


def rule_1(s):

vijfhoek

from typing import Tuple

def rule_0(s):
    if s != '':
        v0 = rule_8(s)
        v1 = (out for inp in v0 for out in rule_11(inp))
        yield from v1


def rule_1(s):

vijfhoek

from typing import Tuple

def rule_0(s):
    if s == '':
        return []

    valid_0 = rule_8(s)
    valid_1 = (out for inp in valid_0 for out in rule_11(inp))
    yield from valid_1