whtsky

// 批量删除广播
function ff(){
    var list = $$('#talkList>li');
    var count = list.length
    console.log('list length', count);
    var t = 0
    var idx = 0
    list.forEach(function(i){
        setTimeout(function() {
            console.log("delete id", i.id, 'idx:', idx++);

whtsky

Process:               mu [16367]
Path:                  /Users/USER/Documents/*/mu.app/Contents/MacOS/mu
Identifier:            org.kreogist.mu
Version:               1.0b5 (1.0.0 Beta 5)
Code Type:             X86-64 (Native)
Parent Process:        ??? [1]
Responsible:           mu [16367]
User ID:               501

Date/Time:             2018-07-16 15:34:32.554 +0800

whtsky

Process:               mu [74693]
Path:                  /Applications/mu.app/Contents/MacOS/mu
Identifier:            org.kreogist.mu
Version:               1.0b5 (1.0.0 Beta 5)
Code Type:             X86-64 (Native)
Parent Process:        ??? [1]
Responsible:           mu [74693]
User ID:               501

Date/Time:             2018-07-13 13:07:33.421 +0800

whtsky

作业提交1.2答案:

1.	
彻底的唯物主义一元论的根本要求是（ ）
	(A)	一切从实际出发
 
2.	

whtsky

function xxxci() {
  $('.commit').map(function () {
    if ($(this).find('.ci-failed')) {
      try {
        $(this).find('.js-pipelines-retry-button')[0].click()
        $('.js-primary-button.btn-danger')[0].click()
      } catch (e) {
      }
    }
  })

whtsky

Keybase proof

I hereby claim:

• I am whtsky on github.
• I am whtsky (https://keybase.io/whtsky) on keybase.
• I have a public key whose fingerprint is 849B C953 6873 EFB9 E491 0C11 7E46 916F 1A78 0568

To claim this, I am signing this object:

whtsky

import random
s = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789^!\\$%&/()=?{[]}+~#-_.:,;<>|\\'


def create():
    return ''.join([random.choice(s) for _ in range(16)])

whtsky

import os
import shutil
import glob

WORKING_PATH = '/Volumes/Kindle/documents'

os.chdir(WORKING_PATH)

for n in glob.glob('*.sdr'):
    name = n[:-4]