Sometimes swift will get some messy by returning _NSContiguousString instead of String if you use .dynamicType
this function will try to help you, to get the class with the easiest way, taking no futher efford.
Last active
March 19, 2016 21:35
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get the classname back from swift.
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| // | |
| // SwiftGetHumanType.swift | |
| // PHPFramework | |
| // | |
| // Created by Wesley de Groot on 02-03-16. | |
| // Copyright © 2016 WDGWV. All rights reserved. | |
| // | |
| // https://gist.github.com/wdg/5cf0f2187c7d31a931b7 | |
| import Foundation | |
| func getHumanClassname(Ob: Any) -> String { | |
| var _ret: String | |
| switch (String(Ob.dynamicType)) { | |
| case "__NSCFNumber", "Int": | |
| _ret = "Int" | |
| break | |
| case "__NSCFBoolean", "Bool": | |
| _ret = "Bool" | |
| break | |
| case "Double": | |
| _ret = "Double" | |
| break | |
| case "_SwiftDeferredNSArray", "Array<String>", "Array<Int>": | |
| _ret = "Array" | |
| break | |
| case "__NSCFString", "_NSContiguousString", "String", "NSString": | |
| _ret = "String" | |
| break | |
| case "_NativeDictionaryStorageOwner<String, Array<String>>": | |
| _ret = "Dictionary" | |
| break | |
| case "protocol<>", "protocol<> -> Bool": | |
| _ret = "Protocol" | |
| break | |
| default: | |
| print("Did'nt found type!, please report it to: https://gist.github.com/wdg/5cf0f2187c7d31a931b7") | |
| print("Found: \(String(Ob.dynamicType))") | |
| _ret = "\(String(Ob.dynamicType))" | |
| break | |
| } | |
| return _ret | |
| } | |
| func getClass(Ob: Any) -> String { | |
| return getHumanClassname(Ob) | |
| } |
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