peters

Connecting Sony WH-1000XM4 to Ubuntu 22.04 (Jammy)

This guide will help you connect your Sony WH-1000XM4 headset to Ubuntu 22.04 using Bluetooth. Once connected, you'll be able to listen to music and use the microphone on apps like Microsoft Teams.

1. Connect to Bluetooth Headset

Steps:

1. Open a terminal and launch bluetoothctl:

rahularity

How To Work With Multiple Github Accounts on a single Machine

Let suppose I have two github accounts, https://github.com/rahul-office and https://github.com/rahul-personal. Now i want to setup my mac to easily talk to both the github accounts.

NOTE: This logic can be extended to more than two accounts also. :)

The setup can be done in 5 easy steps:

Steps:

• Step 1 : Create SSH keys for all accounts
• Step 2 : Add SSH keys to SSH Agent

System-Glitch

# Script to generate a new block every minute
# Put this script at the root of your unpacked folder
#!/bin/bash

echo "Generating a block every minute. Press [CTRL+C] to stop.."

address=`./bin/bitcoin-cli getnewaddress`

while :
do

sappelt

# Import requests and regex library
import requests
import re

def get_external_ip():
    # Make a request to checkip.dyndns.org as proposed
    # in https://en.bitcoin.it/wiki/Satoshi_Client_Node_Discovery#DNS_Addresses
    response = requests.get('http://checkip.dyndns.org').text

    # Filter the response with a regex for an IPv4 address

sdaftuar

Network partition resistance

For the Bitcoin network to remain in consensus, the network of nodes must not be partitioned. So for an individual node to remain in consensus with the network, it must have at least one connection to that network of peers that share its consensus rules. This document describes how we attempt to achieve this.

We can't rely on inbound peers to be honest, because they are initiated by others. It's impossible for us to know, for example, whether all our inbound peers are controlled by the same adversary.

cruxrebels

bool Solution::isPower(int A) {
    if (A<2)
        return true;
  
    for (auto i = 2; i<=sqrt(A); ++i)
    {
        for (auto j = 2; j<=32; ++j)
        {
            if(pow(i, j)==A)
                return true;