seqPromise.js

// Why doesn't this return run p1, run p2, run p3
// currently returns run p1, run p3, run p2

const p1 = () => {
    return  new Promise((resolve, reject) => {
        console.log('run p1');
        setTimeout(resolve, 1000, 'p1');
    })   
};

const p2 = () => {
    return p1().then(() => {
        return new Promise((resolve, reject) => {
            console.log('run p2');
            resolve('p2');
        })
    });  
}

const p3 = () => {
     return new Promise((resolve, reject) => {
        console.log('run p3');
        resolve('p3');
    })
}  

p2().then(p3());