hex_print

hex_print.h

#include <cstdio>
#include <cstdint>

template <typename T>
void hex_print(T v) {
	switch(sizeof(T)) {
		case  1: printf("0x%01X\n", *(reinterpret_cast<uint8_t  *>(&v))); break;
		case  2: printf("0x%02X\n", *(reinterpret_cast<uint16_t *>(&v))); break;
		case  4: printf("0x%04X\n", *(reinterpret_cast<uint32_t *>(&v))); break;
		case  8: printf("0x%08llX\n", *(reinterpret_cast<uint64_t *>(&v))); break;
		case 16: printf("0x%08llX%08llX\n", *(reinterpret_cast<uint64_t *>(&v) + 1), *(reinterpret_cast<uint64_t *>(&v))); break; // for long double (but this is incorrect...!!)
		default: break;
	}
}

test.cpp

#include <iostream>
#include "hex_print.h"

using namespace std;
int main(int argc, char *argv[]) {
	hex_print('B');
	hex_print(4u);
	hex_print(9.0f);
	hex_print(9.2);
	hex_print(9.9l);
	hex_print(9.8l);
	
	return EXIT_SUCCESS;
}

omg,

        case 16: printf("0x%08llX%08llX\n", *(reinterpret_cast<uint64_t *>(&v) + 1), *(reinterpret_cast<uint64_t *>(&v))); break;

is wrong...