Created
August 26, 2011 09:59
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(* | |
Problem 1 | |
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. | |
Find the sum of all the multiples of 3 or 5 below 1000. | |
*) | |
let problem_1 n = | |
let mutable result = 0 | |
let rec loop n r = | |
if n = 0 then r | |
else | |
if (n % 3 = 0) || (n % 5 = 0) then loop (n-1) r + n | |
else loop (n-1) r | |
loop (n-1) result | |
//clever but lazy one, with lists comprehensions (not mine): | |
let problem_1a = | |
([3..3..1000]@[5..5..999] |> List.sum) - ([15..15..1000] |> List.sum) | |
//super, from pdf attached to problem: | |
let problem_1b target = | |
let sum (n) = | |
let p = target / n | |
n*(p*(p+1)) / 2 | |
(sum 3) + (sum 5) - (sum 15) |
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