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format values per thousands using python 3 : K-thousands, M-millions, B-billions.
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| def sizeof_number(number, currency=None): | |
| """ | |
| format values per thousands : K-thousands, M-millions, B-billions. | |
| parameters: | |
| ----------- | |
| number is the number you want to format | |
| currency is the prefix that is displayed if provided (€, $, £...) | |
| """ | |
| currency='' if currency is None else currency + ' ' | |
| for unit in ['','K','M']: | |
| if abs(number) < 1000.0: | |
| return f"{currency}{number:6.2f}{unit}" | |
| number /= 1000.0 | |
| return f"{currency}{number:6.2f}B" | |
| if __name__ == "__main__": | |
| for i in [-123456789, -1, 3.14, 12, 234, 3456, 45678, 567890, 6789012, 78901234, 890123456, 9012345678, 12345678901, 234567890123]: | |
| print(sizeof_number(number=i, currency='€')) | |
| """ | |
| output | |
| ------ | |
| € -123.46M | |
| € -1.00 | |
| € 3.14 | |
| € 12.00 | |
| € 234.00 | |
| € 3.46K | |
| € 45.68K | |
| € 567.89K | |
| € 6.79M | |
| € 78.90M | |
| € 890.12M | |
| € 9.01B | |
| € 12.35B | |
| € 234.57B | |
| """ |
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