the pabilonion method for square root

gistfile1.txt

#include <iostream>

using namespace std;

int main()
{
    int e=1,n;
    cout << "enter the required num : ";
    cin >> n;
    for (int i=0; i<1000 ; i++)
    {
        e = (e+(n/e))/2;

    }
    cout << "the sqr of " << n << " is : " << e;
    return 0;
}