Created
August 21, 2020 06:18
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Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing together the nodes of the first two lists.
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/** | |
* Definition for singly-linked list. | |
* public class ListNode { | |
* public int val; | |
* public ListNode next; | |
* public ListNode(int val=0, ListNode next=null) { | |
* this.val = val; | |
* this.next = next; | |
* } | |
* } | |
*/ | |
public class Solution { | |
public ListNode MergeTwoLists(ListNode l1, ListNode l2) { | |
ListNode newList = new ListNode(); | |
ListNode dummyHead = newList; | |
ListNode l1temp = l1; | |
ListNode l2temp = l2; | |
while(l1temp!=null && l2temp!=null){ | |
if(l1temp.val<l2temp.val){ | |
dummyHead.next = new ListNode(l1temp.val); | |
l1temp = l1temp.next; | |
} | |
else{ | |
dummyHead.next = new ListNode(l2temp.val); | |
l2temp = l2temp.next; | |
} | |
dummyHead = dummyHead.next; | |
} | |
if(l1temp == null){ | |
while(l2temp!=null){ | |
dummyHead.next = new ListNode(l2temp.val); | |
l2temp = l2temp.next; | |
dummyHead = dummyHead.next; | |
} | |
} | |
if(l2temp == null){ | |
while(l1temp!=null){ | |
dummyHead.next = new ListNode(l1temp.val); | |
l1temp = l1temp.next; | |
dummyHead = dummyHead.next; | |
} | |
} | |
return newList.next; | |
} | |
} |
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